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http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w11_qp_33.pdf
help needed in Q1o...Dug thanks in advance
help needed in Q1o...Dug thanks in advance
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you first plot points A and B on the diagram and i am assuming you know how to do thatSomeone help!!!!! http://www.novapapers.com/images/PDF/CIE/A-LEVEL/maths/2011nov/9709_w11_qp_33.pdf
P3 q6 part 2. Its an argand diagram question! Please help
I = ⌡(tan^(n+2) x + tan^n x) dxhttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_33.pdf
help needed in Q1o...Dug thanks in advance
part 2 is easy i hope you can do it nowhttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_33.pdf
help needed in Q1o...Dug thanks in advance
a better dialogue p3 p3 every where xD. anyway in s1 heres a good one there are 9 pies to be divided between 3 people so that each person gets a odd no of pies. in how many no of ways can they be divided. i know the answerso i am posting it so u guys can solve it and others can get help.
please pure 1 jun2010 v11 no.10 and n0.8 iii .
please pure 1 jun2010 v11 no.10 and n0.8 iii .
i ) OB = OA + OC
OB = 4i + 2j + 4k
Unit Vector of OB = (4i + 2j + 4k) / (√4^2+2^2+4^2)
= (4i + 2j + 4k)/6
ii) AC = OC - OA
AC = 2i -4j - 2k
Now use the scalar product formulae
OB = 4i + 2j + 4k
AC = 2i -4j - 2k
AC * OB = |AC| * |OB| * Cos(Theta)
(4*2)+(2*-4)+(4*-2) = 2√6 * 6 * Cos(Theta)
-8/12√6 = Cos(Theta)
Theta = Cos^-1(-8/12√6)
Theta = 105.8 Degrees
They asked for acute angle = 180 - Ans
= 74.2 Degrees Answer
iii) 2 * (Magnitude of OA + Magnitude of OC)
2 * (|OA| + |OC|)
2* (√19 + √11)
= 15.35 Answer
THANK YOU8iii) The perpendicular bisector of AB meets BC at D.
Perpendicular bisector of a line is always from the middle of the line (Midpoint of the line) and is 90 Degrees to the line.
So find the co-ordinates of midpoint.. then find the equation of normal on the midpoint (normal gradient = -m/2 as [2m * grad = -1])
Then simultaneously solve equation of Normal (of AB) and equation of BC.. to get the co-ordinates of D.
ahmed abdulla syed1995 A star
This of pure 1, no Mechanics nor Physics knowledge needed.
as you did,
2(1-0.75^n)/1-0.75
but we also have to multiply with 2, since when a bounces it goes up and down so it travel the distance twice not once, except for the first where it only go down, then bounces..therefore
{[2(1-0.75^n)/1-0.75] x 2} -2
[8-8(0.75^n)] x 2 -2
16 - 16(0.75^n) - 2
14 - 16(o.75^n)
(b) sum of infinity
(2/1-0.75) x 2 -2
8 x 2 -2
16 -2
14.
link please?Please Help jun2010 v.12 pure 1 no.7 (a)
the ball travel the first time once...then twice after ward...so u multiply with 2 but u minus the first 2 meters
bro .... can i now why the .... -2 after multiplying with2
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