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Mathematics: Post your doubts here!

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2Nir6.png


You're freaking out :p

Yea that's the answers i got.. I just shifted the 2 of n/2 to the other side to make it easier to work with:p

i got

d=2
16=2a-d
16=2a-2
2a=18
a=9

Answer
i still don't get it... how did u get S1=9 ?? :'( sorry for the big time bother but this question is beating the hell out of me -___-
 
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i still don't get it... how did u get S1=9 ?? :'( sorry for the big time bother but this question is beating the hell out of me -___-
ok i only remember the first part of this question because this is a tricky question so i can't get it out of my mind till this day see

u have the total sum of all the terms formula given..if u substitute 1 in that formula it means u r finding the total sum of 1 term which is 9 so thats our first term got me ?
 
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Ok wow that was really a slap-in-face kind of simple!! :O x_x
thankuu so much iKhaled and MustafaMotani :)
i seriously don't know how these cie people do this!! they just get into ur heads and play mind games with u given just over an hour with them and them not even being present!! :O >__< urgghh
 
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Ok wow that was really a slap-in-face kind of simple!! :O x_x
thankuu so much iKhaled and MustafaMotani :)
i seriously don't know how these cie people do this!! they just get into ur heads and play mind games with u given just over an hour with them and them not even being present!! :O >__< urgghh
CIE examiners r really experts because they know how even if u solved allll the past papers in the world for a subject, the one which u will do in the exam will be different to all of what u did and will be able to trick u!
 
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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_12.pdf

Question 7 part b..

I mean I solved it but didn't really get the concept behind it..

Can someone solve that question for me?
see in gp
the formula of term t s given by ar^(n-1)
first term=a
2nd term n2= ar^(2-1)= ar
3rd term n3= ar^(3-1)= ar^2

the second term is nine less than the frst
a- ar=9.....i
the second term and thrd term add up to give 30
ar+ ar^2 =30
solve simultaneously
 
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see in gp
the formula of term t s given by ar^(n-1)
first term=a
2nd term n2= ar^(2-1)= ar
3rd term n3= ar^(3-1)= ar^2

the second term is nine less than the frst
a- ar=9.....i
the second term and thrd term add up to give 30
ar+ ar^2 =30
solve simultaneously

haha .. one gets the same answers though. this methods clears my mind up! Thanks
 
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