Mathematics: Post your doubts here!

[MustafaMotani]

syed1995 i dont know what codone means.. but i would recommend u give 27..
reason : if a=1.5 then second term = -7.5 (negative)
since question clearly says that all the terms are positve i would recommend 27

 

[Rutzaba]

haha .. one gets the same answers though. this methods clears my mind up! Thanks

anytime... unless its four in the morning

 

[sma786]

Does anyone have the 2013 paper 1 specimen?!

 

[syed1995]

Does anyone have the 2013 paper 1 specimen?!

specimen paper only comes when there is a big change in the syllabus or paper pattern.. which there hasn't been .. so no specimen papers..

 

[syed1995]

syed1995 i dont know what codone means.. but i would recommend u give 27..
reason : if a=1.5 then second term = -7.5 (negative)
since question clearly says that all the terms are positve i would recommend 27

Yea that's why i rejected the answer the instant i got it. but got confused after seeing the MS.

 

[syed1995]

anytime... unless its four in the morning

haha so true.

 

[MustafaMotani]

Yea that's why i rejected the answer the instant i got it. but got confused after seeing the MS.

then better not see it..

 

[sma786]

specimen paper only comes when there is a big change in the syllabus or paper pattern.. which there hasn't been .. so no specimen papers..

thank god, means the paper is going to be similar to the previous ones

 

[syed1995]

thank god, means the paper is going to be similar to the previous ones

I hope not.. the 2012 papers were extremely difficult!

 

[abruzzi]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s12_qp_13.pdf
Please help me with question no. 11(iv).. I don't understand how the marking scheme did it.

 

[nafis shahRiyar]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_13.pdf
Please help me with question no. 11(iv).. I don't understand how the marking scheme did it.

plot g(x) and then reflect it in x=y line in order to get g(x^-1)

 

[mominzahid]

wen we square a line and integrate fr given limits it gives us the volume under that p[articular line or curve
wen there is no line given and its a straight line parralel to x axis the eq of line wud be y=2

now see volume under y=2 gives us the complete vol under line ie the whole rectangle
no we dun need the non shaded region of the rectangle
non shaded region of rectangle = vol under the curve

now u kno
vol of shaded + vol of non shaded = vol of total rectangle
so vol of shaded = total (under y=2) - non shaded (under curve)
ask again if u dun get it

Hey... THANKS ALOTT..
I was stuck at this stupid question for over an hour and turns out it was the simplest thing.
Thanks alot again

 

[mominzahid]

y=2 is the equation of the straight line
the area under the shaded region = area under line - area under graph

that is why we had to subtract the two integrals

I got it.. Thanks alott..
Really Appreciate it

 

[nafis shahRiyar]

http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_w12_qp_12.pdf

i dont understand question 11 :| can someone explain?

 

[PANDA-]

I hope not.. the 2012 papers were extremely difficult!

Same, the 2012 papers were just wrong. I hope they make it easy

 

[syed1995]

Same, the 2012 papers were just wrong. I hope they make it easy

And the threshold wasn't any lower either!

 

[abruzzi]

plot g(x) and then reflect it in x=y line in order to get g(x^-1)

Yeah.. but how do I get the y-intercept and x-intercept??

 

[PANDA-]

And the threshold wasn't any lower either!

How much do you get on average when solving P1? As in past papers.

 

[nafis shahRiyar]

Yeah.. but how do I get the y-intercept and x-intercept??

you dont have any intercept in this graph,look carefully the range is given from k<x<4 and where you found k=2
so,when x is 2,y is 8
when x is 3,y is 7 and when x is 4,y is 4.
plot them and join the curve

 

[daredevil]

I got it.. Thanks alott..
Really Appreciate it

np