Mathematics: Post your doubts here!

[syed1995]

out of 75? :O

YEA! .. i am not that bad in maths to get 60% -,-

 

[MustafaMotani]

Rutzaba underestimated you syed1995

 

[syed1995]

Rutzaba underestimated you syed1995

I don't know why people do that .. Honestly getting underestimated is way better than having expectations and not being able to meet them So I am good.

 

[MustafaMotani]

I don't know why people do that .. Honestly getting underestimated is way better than having expectations and not being able to meet them So I am good.

agreed ..

 

[ZainH]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w11_qp_12.pdf

Q4)ii) I'm clueless .___.

 

[syed1995]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_12.pdf

Q4)ii) I'm clueless .___.

Equate both the equations.. you will have a equation in terms of k..

b^2 -4ac = 0 for the curve to be intersecting at only one point..

you will get the value of k.

 

[ahmed abdulla]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_12.pdf

Q4)ii) I'm clueless .___.

make "y" as subject in BOTH cases ...and equate the two ... and arrane in form of quadratic eqn ... finally use b^2-4ac=0 since it intersect and find "K" value

 

[MustafaMotani]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_12.pdf

Q4)ii) I'm clueless .___.

for line to be tangent it should just cut the curve at one point, in other words just touch the curve.
for such scenario b^2-4ac = 0

first make x the subject from the line equation and then substitute it to the curve equation. You will be left with quadratic equation of y .... now simply apply b^2-4ac=0

 

[ZainH]

Equate both the equations.. you will have a equation in terms of k..

b^2 -4ac = 0 for the curve to be intersecting at only one point..

you will get the value of k.

I tried that, I'm pretty sure I'm using b^2-4ac wrong.
This is the equation I'm getting when they're equated: y^2+2k-4y-13 = 0 ..

What's A , B and C... 4 terms. I forgot how to do these x_x

 

[ahmed abdulla]

MECHANICS ....
can any one give my the idea of how to do this question ... i dont have nothing to do !
http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w07_qp_4.pdf
q7 (ii) and (iii) ????????

 

[syed1995]

I tried that, I'm pretty sure I'm using b^2-4ac wrong.
This is the equation I'm getting when they're equated: y^2+2k-4y-13 = 0 ..

What's A , B and C... 4 terms. I forgot how to do these x_x

You need to take the equation in terms of X.

 

[ZainH]

You need to take the equation in terms of X.

All right, in that case I get : x²+8x+k²-52 = 0

 

[MustafaMotani]

MECHANICS ....
can any one give my the idea of how to do this question ... i dont have nothing to do !
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w07_qp_4.pdf
q7 (ii) and (iii) ????????

bro if p moves up then it means tension has to be greater than all the opposing forces

hope it helps.. as for part iii i dont have m1 so i dont know wahts coeffiecient of friction..

 

[Maz]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_qp_12.pdf
3(ii) Please!
Thnx.

 

[xhizors]

I tried that, I'm pretty sure I'm using b^2-4ac wrong.
This is the equation I'm getting when they're equated: y^2+2k-4y-13 = 0 ..

What's A , B and C... 4 terms. I forgot how to do these x_x

in b2-4ac put these values from ur eq
(2k-4)^2-4(1)(-13)

 

[MustafaMotani]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_12.pdf
3(ii) Please!
Thnx.

its easy if you have done part (i)

its just like finding minimum value of the function..

first find dA/dx and then equate it to zero ... whatever value u get for x ... substitute that value in original function to get the minimum area..

 

[GorgeousEyes]

please nov 07 no 3 ii

 

[syed1995]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_12.pdf
3(ii) Please!
Thnx.

dA/dx = 0 .. find x.

Equate x into the A equation..

 

[Rutzaba]

I dint guys i asked

 

[ZainH]

in b2-4ac put these values from ur eq
(2k-4)^2-4(1)(-13)

That doesn't work :|
K doesn't come as 8.5.