Mathematics: Post your doubts here!

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daredevil said:
no problemo :) butt ummm *ahem ahem not a boy ahe ahem* :p
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see the he proved my point :D . i am not alone in this world xD

daredevil said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w08_qp_1.pdf

i'm not getting the correct answer for Q 5 :O
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the whole question here goes
5i) -2=a-bcos(0r 360) cause in inverted graph ) 0 or 360 whould have lowest value
10=a-bcos(180) now solve them simultaneously
5ii) a-bcos(x) = 0 solve it by sub the values of a and b found in first part

5iii) well draw the graph it will be a inverted graph of cos translated a times with amplitude of b i guess
 
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Magenta said:
The angle of the bigger sector is 2π - (angle of smaller sector) and the angle of smaller sector is π-1 so
2π-(π-1) = 2π-π+1 = π+1
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daredevil said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_1.pdf

Q 5.... why is it R2 = ½r ² (π + 1)
why π + 1 ??

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_ms_1.pdf

Q 10 why is it -5 ??? -__-
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use the easier aproach of area of circle - R1 it would save time as it is straight forward
 
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Thanku Magenta and A star :D
those were pretty simple actually o_O I guess its just the last minute stress taking the toll on me :p never mind -_- :p
and hahah yeah A star I was thinking the same thing :p lolx My avatar did it again :p xD
 
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daredevil

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A star said:
i
this ones easy u know that its is defined for values greater then p/2 hence the two values u get one is lesser then p/2 other greater i:e 2.8 will be accepted other rejected
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ohh right.... c another one of those imbecile attacks *silly me* :p thanks a bunch :)
 
Jiyad Ahsan

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A star said:
i
this ones easy u know that its is defined for values greater then p/2 hence the two values u get one is lesser then p/2 other greater i:e 2.8 will be accepted other rejected
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bla bla guys you should stop worrying so much, im sure everyone will do fine (though i hope not too fine :p it'll push up the threshold) anyways
umm after you get the sin^-1(1/3) the basic angle you get is 0.340 radians and since the given range is between 1/2pi and 3/2 pi we get,
x=pi - 0.340 = 2.80 radians

therefore g^-1(3) = 2.80
 
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Jiyad Ahsan said:
bla bla guys you should stop worrying so much, im sure everyone will do fine (though i hope not too fine :p it'll push up the threshold) anyways
umm after you get the sin^-1(1/3) the basic angle you get is 0.340 radians and since the given range is between 1/2pi and 3/2 pi we get,
x=pi - 0.340 = 2.80 radians

therefore g^-1(3) = 2.80
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ikr i was telling daredevil the same thing just answering her questions :p
 
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