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thanksSn=360
a=3
d=2
Pluck these values in
Sn=n/2 (2a +(n-1)d)
and yu shall get n
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thanksSn=360
a=3
d=2
Pluck these values in
Sn=n/2 (2a +(n-1)d)
and yu shall get n
no noproblem go i did it anywayA star i have to go right now but i'll do it and post later today
i have done a bit of it actually
just the equations are complicated otherwise its just like any other such question
just do it with a clear head and fresh start and u'll be able to do it
link please + varientI want nov.012 no.7 ii please .
AB = b -a = (k-1 , -k, 2k - 2)
you will have it tmrw ,dont be impatientDoes anyone have may/june 2013 paper 1 variant 12 with marking scheme ? Please i need it urgently
you will have it tmrw ,dont be impatient
it will cost u nearly half a million dollars/euros/pounds in bribeDoes anyone have may/june 2013 paper 1 variant 12 with marking scheme ? Please i need it urgently
well cant do anything about it I guess even money wont work A star .tomorow it wont be of any use
haha that why i was asking if someone else had it i dont have that kinda moneyit will cost u nearly half a million dollars/euros/pounds in bribe
cant you let a guy make some moneywell cant do anything about it I guess even money wont work A star .
haha that why i was asking if someone else had it i dont have that kinda money
cant you let a guy make some money
haha xD pay it or forget it xD
3a where dot product =0http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_12.pdf
Question- 10 (a)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_12.pdf
Question- 3(a)
Please.. Thank You
thanksAB = b -a = (k-1 , -k, 2k - 2)
Unit vector = vecter/ magnitude
Therefore, (k-1, -k, 2k-2)/[sqrt] (k-1)^2 + (-k)^2 + ((2k -2)^2
Since they have said that the vector AB is the unit vector, the magnitude would equal 1.
Equate the magnitude you should get the answer.
hahahah sure sure ,but the chance is only if the person is soft hearted and generous enough.cant you let a guy make some money
haha xD pay it or forget it xD
Does anyone have may/june 2013 paper 1 variant 12 with marking scheme ? Please i need it urgently
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