i wish i had a double like optionLets hope our marks are just as high
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i wish i had a double like optionLets hope our marks are just as high
A starokay ppl listen up
do Q8 from this one -__-
i'm dead exhausted and can't solve it so help :O
ok here goes nothingokay ppl listen up
do Q8 from this one -__-
i'm dead exhausted and can't solve it so help :O
takes time typing
I solved it just yesterday.okay ppl listen up
do Q8 from this one -__-
i'm dead exhausted and can't solve it so help :O
got it was using a instead of 2aI solved it just yesterday.
Now write down the numbers for the first model: they are going to be 1000,2000,3000,...
5 percent donated everyday, 50,100,150.
first term is 50, common difference is 50.
solve for the sum of 40 terms. you get 41000
For the second model, do the same. 1000,1100,1210,1331...
r= 1.1
S40=1000(r^40-1)/(r-1)
what ever you get just take the 5 percent of that.
i am getting 40000
Im getting 41000. even by solving what YOU typed up there.i am getting 40000
Shit happens dude
Just make sure it doesnt tomorrow.
TOMORROW*Exactly lol, emphasis on TOMORROW.
can you tell me how to make Q7 iii plshttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_12.pdf
There's a problem in 6(i) right?
easy 2x-3<1Q. A geometric progression has the first term 4, and common ration (2x-3) , find the set of values of x for which the geometric progression has a sum to infinity.
How ?
r<1 if sum to infinity existsQ. A geometric progression has the first term 4, and common ration (2x-3) , find the set of values of x for which the geometric progression has a sum to infinity.
How ?
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