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Mathematics: Post your doubts here!

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If f(x)=x²-4x+7 for x>2 and g(x)= x-2 for x>2

The function h is such that f=hg and the domain of h is x>0
Q. Obtain an expression for h(x) .


well u know how we to the fg(x) we take the f function and put the g function in the place of x of the f funtion and solve it??
here it is kinda the same deal... the difference is that they have given u another letter to confuse u :p
if f=hg then f-1(g)=h
now find f^-1 and substitute the g function there in place of x and solve it :)
what u get for the answer as an expression is h
if u stil don't get it think over it a lott!!! and then take a break and come here again :) at least some of us will still be here in the wee hours too :p we're that paranoid :p

I actually understood, not from what you explained.. but while reading I realized what we had to do xD
Anyways thanks! You too doctorofelectronics
 
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okay ppl listen up :p

do Q8 from this one -__-
i'm dead exhausted and can't solve it so help :O
 

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okay ppl listen up :p

do Q8 from this one -__-
i'm dead exhausted and can't solve it so help :O
ok here goes nothing
1 on first day the amount donated is 5/100 *1000= 50
on second day the amount donated is 5/100 *2000=100 hence we can see that d=50 a=50 now use formulae S40=40/2(100 + (39)50) =40000
 

asd

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okay ppl listen up :p

do Q8 from this one -__-
i'm dead exhausted and can't solve it so help :O
I solved it just yesterday.
Now write down the numbers for the first model: they are going to be 1000,2000,3000,...
5 percent donated everyday, 50,100,150.
first term is 50, common difference is 50.
solve for the sum of 40 terms. you get 41000
For the second model, do the same. 1000,1100,1210,1331...
r= 1.1
S40=1000(r^40-1)/(r-1)
what ever you get just take the 5 percent of that.
 
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I solved it just yesterday.
Now write down the numbers for the first model: they are going to be 1000,2000,3000,...
5 percent donated everyday, 50,100,150.
first term is 50, common difference is 50.
solve for the sum of 40 terms. you get 41000
For the second model, do the same. 1000,1100,1210,1331...
r= 1.1
S40=1000(r^40-1)/(r-1)
what ever you get just take the 5 percent of that.
got it was using a instead of 2a :p
 
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