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Using s=ut+0.5at^2, Hp=12t+0.5(-10)t^2 => Hp=12t-5t^2
Q6,i) See triangle ABR, use cosine rule,
Because it says, 'at the instant when the string breaks', that means as P has a greater weight, it will fall towards the ground (downwards) and Q will travel upwards. therefore the velocities will have opposite directions. as P travelling down with for eg +V nd Q upwards with -V...or vice versa.
yeah paper 4 and 1 only i'm AS-level
I think its not possible that after the string break Q will travel up...the sign is maybe because Q was first travelling up and now down and as velocity is a vector so it changes sign !
Firstly, the sign aint specified in the mark scheme and yeah What i said was right...ya know how...when initially the string breaks, p is heavier so q will travel a distance upward and as P hits the ground, then Q will fall downwards. As the question later says 'Q reaches the ground 0.8 secs later than P'...if both were to fall to the ground at the instant the string breaks they both would reach the ground at the same time as they are the same height above the ground...Think logically...I think its not possible that after the string break Q will travel up...the sign is maybe because Q was first travelling up and now down and as velocity is a vector so it changes sign !
Thanks anyways
For particle P:
u=20, a=-10,
s=ut+0.5at^2
s=20t+(0.5 x -10 x t^2)
s=20t - 0.5t^2
For Particle Q:
u=25, a=-10, time=t-4
s=25(t-4) - 0.5(t-4)^2
After simplifying you get
s=29t + 10.8 - 5t^2
Now equate both the distances :
20t-0.5t^2 = 29t + 10.8 -5t^2
After solving this you'll get t=1.2
For Particle P:
v=u+at
v=20+(-10 x 1.2) = 8m/s
For Particle Q:
v=25-10(t-0.4)
v=25-10(1.2-0.4) = 17m/s
I hope you got it
I would but I got mechanics tomorrow. If you can wait then I shall explain you by tomorrow In sha Allah!
No problem, really. I have the exam 8 days from now, so tytI would but I got mechanics tomorrow. If you can wait then I shall explain you by tomorrow In sha Allah!
and super good luck insha'a Allah
I would but I got mechanics tomorrow. If you can wait then I shall explain you by tomorrow In sha Allah!
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