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Mathematics: Post your doubts here!

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Youu are great mash'allah (y) thank youuu :)

You're welcome x)

sinx/cosx =wg/5.5
tanx * 5.5 = wg

Substitute this in the second equation
5.5cosx + sinx( tanx * 5.5) = 7.3
after simplifying the brackets, you'll get
5.5cos^2 x + 5.5 sin^2 x = 7.3 cosx
5.5( cos^2 x + sin^2 x) =7.3 cosx
5.5/7.3 = cosx
x= 41.4

now wg= tan41.4 * 5.5

Thank you, my brain stopped e_e
 
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Oh that's easy just make 2 simultaneous equations.
Use s=ut+1/2at^2

So your first equation is: 55=5u+12.5a
And second one is: 120=10u+50a

Solve them simultaneously, you should get a=0.4 and u=10 m.s-1
where did the 2nd equation come from? :/
 
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Oh righttt.. i was using B to C... -_-
Anyways q4(ii) same paper?

Just add up your values of the forces in the y-direction , and they've already given you the ones in the x-direction.
Use Pythagoras to find resultant, and then use whatever to find the angle .

Hope you got it x)
 
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Just add up your values of the forces in the y-direction , and they've already given you the ones in the x-direction.
Use Pythagoras to find resultant, and then use whatever to find the angle .

Hope you got it x)
By what time will u be here to help? im still doing papers and problems are arising.. :/
and will u also be available in the morning?
 

Tkp

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June011 v.43 no.4 and no.5 please ,, Honestly they are the worst questions ever :(
for keeping the block equilbrium a frictional force must act on the block in the right direction
so 6.1+5cos theta=f
f=7.5
2)f=ur
r=12.5
3)7.5-8.6-5cos theta=ma
 
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By what time will u be here to help? im still doing papers and problems are arising.. :/
and will u also be available in the morning?

I'll be here till like 11, which is 3 more hours I guess.

I won't be here in the morning though.
 
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