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Mathematics: Post your doubts here!

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MustafaMotani can you please summarize some formulas for each different cases of vector question, like when plane is perpendicular to one line.. and other complicate situation? I kept on trying to understand the question, but I always got confused at deciding each formula I should use..
 
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PhyZac
to be honest, from this step, you could (i would) directly jump to the conclusion. which is the prove.

As for Q8i) you're getting -10. that's correct. now you have to change signs because the limits have been exchanged. If you notice the limits are supposed to be (6-5)^1/2 and (6-2)^1/2
1 being your upper limit and 2 being the lower limit. However the question asks ask to write 2 as the upper limit and 1 as the lower limit. So when you exchange these limits you have to change the sign

Sounds a bit confusing but think about it, you'll get it
 
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2.i) Let f(x)=x^3-8x-13
By trial n error
(as in take values of x= 0 to any no. as long as u dont get two a positive value; u may Consider decimals too sometimes)

so i found for x=3 we get a negative value which is -10
And for x=4 we get a positive valu which id 19
so as the values have different signs the root lies betwn x=3 n x=4

Hope u got this!

Btwn working on 6 i .... gotta wait!!
 
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[/COLOR said:
Rutzaba]light is abt to go...
try making factors of dnominator
2x^2 +5x+2
(1+2x)(x+2)
do partial fractions
integrate


I just don't get why there are 3 terms instead of 2?
 
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2.i) Let f(x)=x^3-8x-13
By trial n error
(as in take values of x= 0 to any no. as long as u dont get two a positive value; u may Consider decimals too sometimes)

so i found for x=3 we get a negative value which is -10
And for x=4 we get a positive valu which id 19
so as the values have different signs the root lies betwn x=3 n x=4

Hope u got this!

Btwn working on 6 i .... gotta wait!!

I don't understand one thing. I mean, how do you know which value of x is the correct value? Because even if I take x=2, I get a negative value of -21.
And even if I take x=5, I get a positive value of 72. So how do I know which value of x to consider? :(
 
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I don't understand one thing. I mean, how do you know which value of x is the correct value? Because even if I take x=2, I get a negative value of -21.
And even if I take x=5, I get a positive value of 72. So how do I know which value of x to consider? :(

yes i knw that is confusing... Bt wat u do is start from zero n go serially n if u get two different signs consecutively those are the two values of x! like over here u cud have said x lies betwn 0 to 5 but to be precise u have to say 3 to 4.
U c 4 x=3 u get positive value n for x=4 u get negative so they u get different values consequentially so the root lies betwn this two...
Umm cud i make the point? :~

Btwn i also told u the procedure of 6i ! c inbox!!!
 
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yes i knw that is confusing... Bt wat u do is start from zero n go serially n if u get two different signs consecutively those are the two values of x! like over here u cud have said x lies betwn 0 to 5 but to be precise u have to say 3 to 4.
U c 4 x=3 u get positive value n for x=4 u get negative so they u get different values consequentially so the root lies betwn this two...
Umm cud i make the point? :~

Btwn i also told u the procedure of 6i ! c inbox!!!
Oh okay :) Thanks!
 
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