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Mathematics: Post your doubts here!

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Hello,
could you help me please? I'm having a hard time with number 5 (iii). I have got 2sec^2X - 1 - 2 secXtanX. There is a sign problem. :( :$
Please help me.
 

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Hello everyone
I am new to this part of Xtremepapers cuz i hv just finished my O levels n in these vacations i wanna study for A levels .Although i created a thread but there was no reply. Actually i need the name of the best books for Math A levels that most renown skools follow.
hey man, use this site will prepare u very well for the maths papers

http://www.examsolutions.net/
 
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could you help me please? I'm having a hard time with number 5 (iii). I have got 2sec^2X - 1 - 2 secXtanX. There is a sign problem. :( :$
Please help me.


Similar to the question above that one, you'd simply have to expand ( sec + tan ) ^2
sec^2 + 2sectan + tan^2
sec^2 + 2sectan + sec^2 - 1
What's the problem?
 
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Similar to the question above that one, you'd simply have to expand ( sec + tan ) ^2
sec^2 + 2sectan + tan^2
sec^2 + 2sectan + sec^2 - 1
What's the problem?

Thank you so much.........I had not link that part with the question above. Thank you. <3 ^^
 
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Guys, number 7 ii and 8ii pls. Thanx!..
As for 7ii)
You have the derivative of the equation, also known as "y dash". To get the original curve you simply need to integrate. So...
5 becomes 5x and -8/x^2 becomes +8/x. However, there is the constant of integration, so the final thing is. y = 5x + 8/x + c.
Point P is on the curve thus it satisfies the curve's equation. Substitute with its coordinates to find c.

As for 8ii)
First you find the intersections with the x-axis ( By putting y = 0 ). Those will be the limits of integration. The volume needed has a specific formula which is PI *int(y^2 dx)
y^2 = 8x - x^2
int ( 8x - x^2 dx ) = 4x^2 - x^3 / 3
Substitute with the limits and don't forget to multiply by PI.
 
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As for 7ii)
You have the derivative of the equation, also known as "y dash". To get the original curve you simply need to integrate. So...
5 becomes 5x and -8/x^2 becomes +8/x. However, there is the constant of integration, so the final thing is. y = 5x + 8/x + c.
Point P is on the curve thus it satisfies the curve's equation. Substitute with its coordinates to find c.

As for 8ii)
First you find the intersections with the x-axis ( By putting y = 0 ). Those will be the limits of integration. The volume needed has a specific formula which is PI *int(y^2 dx)
y^2 = 8x - x^2
int ( 8x - x^2 dx ) = 4x^2 - x^3 / 3
Substitute with the limits and don't forget to multiply by PI.

Thanx a lot! :D...However , I didn't understand something.The required volume is pi*y^2*dx....so before we integrate, dont we square the equation 8x -x^2????
 
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Thanx a lot! :D...However , I didn't understand something.The required volume is pi*y^2*dx....so before we integrate, dont we square the equation 8x -x^2????

The equation itself is root(8x-x^2) so when it is squared, the root is just omitted and that's it. :)
 
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