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Take the x common. You'll get (x)(1 - x^2) < 0. That makes two roots, (x) < 0 and (1 - x^2) < 0. The first one's solved in itself, for the second one you just go about it as a regular equation; 1 < x^2 and then under-root both the sides and you'll get x > 1. I think I might be wrong here though but hopefully somebody can guide us both a bit here, or maybe you'll get it.How to solve the inequality: x-x^3 < 0
please help