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Ah! i forgot to consider the modulus...anyways JazakAllah...tyhere's the solution to 10 part 3 https://www.xtremepapers.com/community/threads/a-maths-doubt.24710/
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Ah! i forgot to consider the modulus...anyways JazakAllah...tyhere's the solution to 10 part 3 https://www.xtremepapers.com/community/threads/a-maths-doubt.24710/
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_33.pdf
Q) 3 ii) What's the area to be shaded??? Please
the area inside the circle if i'm not mistaken
because u'll have |z - (3 + 4i)| =< 5
$~SauD~$ m i right?
yes, you are right
btw, guys.. stupid doubt..
how is 3+4i as 5 on the right side?
do u mean like 5 =< |z - (3 + 4i)| ?
it's w^2 on the right, right?
so should it be 3+4i just like on the left?
yes...
on the right is the modulus of 3 + 4i and the left is the complex number itself
not sure if this is what ur saying
yes...
on the right is the modulus of 3 + 4i and the left is the complex number itself
not sure if this is what ur saying
yes modulus of 3+4i is 5? :s how so?
Hi there
May I please get help with question 7b?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_32.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_ms_32.pdf
If possible, could you please show me a diagram of the correct answer and an explanation?
Thank you!
Just put in the value of a point to check which side of the line gives smaller value of |z| than |z-2-2i| eg.z=i.https://skydrive.live.com/redir?resid=8E431BE676F5BD8!1202&authkey=!AH77uTDQqhkEH5E&v=3
Just donno where to shade.. |z| < 2 shows to shade whole circle.. But then i am confused with the other inequality..
Sorry.
that is correct, except you use dotted lines for both the circle and the y=2-x line because its < not smaller or equal to.https://skydrive.live.com/redir?resid=8E431BE676F5BD8!1202&authkey=!AH77uTDQqhkEH5E&v=3
Just donno where to shade.. |z| < 2 shows to shade whole circle.. But then i am confused with the other inequality..
Sorry.
Just put in the value of a point to check which side of the line gives smaller value of |z| than |z-2-2i| eg.z=i.
that is correct, except you use dotted lines for both the circle and the y=2-x line because its < not smaller or equal to.
You shade the bottom part of the circle, that is the quarter circle occupied in 2, 3 and 4 quadrant and shade the area below the y=2-x line (the triangle) in the first quadrant.
it's the big one, substitute any point eg. -1-iThanks bud
it is smaller dude.. :/
Thanks..
it's the big one, substitute any point eg. -1-i
|z| < |z − 2 − 2i|
|-1-i| < |-1-i -2-2i|
|-1-i|< |-3-3i|
square root 2 < 3 square root 2
and -1-i is below the bisector, so you shade the big one.
unless I'm doing something really wrong
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