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please help me with these questions http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_61.pdf Q3
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s12_qp_63.pdf Q2ii
I expanded Σ(x-36)^2 it to pull out the term Σx^2. That is what we are supposed to find.
Consider this example:
(a+b)^2 = 4
a^2 + 2ab + b^2 = 4
If we are given 'ab' and 'b^2', we can easily find a^2 by putting the values into the equation. My solution is exactly the same. Did you get it now?
ii) Probability of length less than 73 m and length greater than 77 m is the same since they are the same distance from mean. A normal distribution curve is symmetric about its mean.
P(X<73) = P(X>77) = 0.15
Let X represent the number of rolls having length greater than 77 m.
n = 8
p = 0.15
q = 0.85
P(X<3) = P(X = 0) + P(X = 1) + P(X = 2)
P(X<3) = (8C0) (0.85)^8 + (8C1) (0.15)(0.85)^7 + (8C2) (0.15)²(0.85)^6
P(X<3) = 0.895
You use the formula and you will get some termshttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s03_qp_1.pdf
Question 1.
What's the method? I know the formula, how do we get the coefficient for 1/x
Help please. Thanks
That makes sense. I did it but my answer is coming as +40. Mark scheme says -40, can you tell me where I went wrong?You use the formula and you will get some terms
like x^5,x^4,x^3.........
you will also get a x^-1 term as you say you know the formula you might also know how to apply it
Therm Multiplying with x^-1 will be the coefficient
If you don't get this i can expand it for you and show you
how to find the roots. I have pasted question for your easiness
Please help
X and Y are related by x^n y = c
When we form equation it should be : nlogx +logy = logc
But in marking scheme they use (( ln )) instead of log ! how comes ?
4th term : 5C3 *(2x)^2 * (-1/x)^3That makes sense. I did it but my answer is coming as +40. Mark scheme says -40, can you tell me where I went wrong?
4th term : 5C3 *(2x)^2 * (-1/x)^3
= 10 * 4x^2 *-1/x^3
= 40x^2 * -1/x^3
= x ( 40 *-1/x)
Welcome back sayeddoesn't matter whether you use log or ln.. you will get the same answer in the end as only the base is changed in one it's e and other 10... However it is preferred to use ln instead of lg because of presence of e(exponential) in some questions which can easily be resolved with ln.
It's impossible. But when you use ln, when taking antilog use e^X instead of 10^x.Welcome back sayed
I tried to use both , i got the right answer with ln but a wrong answer with log!
you can even check it yourself , mj2010 , va'31 question 3
For 9 iihttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s04_qp_1.pdf
Question 9 ii and iii. With explanation please
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