Mathematics: Post your doubts here!

[ZaqZainab]

okay got it.
it will be parallel because sp and qr are both perpendicular to SR. got it. thanks.

exactly

 

[Suchal Riaz]

exactly

actually the diagram was a bit misleading. but i appreciate the efforts that you put into it. really learned something. thanks.

 

[David Hussey]

can someone help me in http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s09_qp_3.pdf
q3i
q6ii
7i
this is one crazy paper :/

 

[SitiPutri]

can someone help me in http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_3.pdf
q3i
q6ii
7i
this is one crazy paper :/

Sorry not an A2 student so cant really help much. But this is for Q3i

 

[sumeru]

can someone help me in http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_3.pdf
q3i
q6ii
7i
this is one crazy paper :/

For 7(ii)...i have attatched a solved one yesterday..so look above you'll find it.....and for 7(i) use quadratic equation to find the roots...

 

[daredevil]

can someone help me in http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_3.pdf
q3i
q6ii
7i
this is one crazy paper :/

 

[daredevil]

can someone help me in http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_3.pdf
q3i
q6ii
7i
this is one crazy paper :/

for 7i
either use the quadratic formula such that
a=1 , b=2(sqrt)3 i c= -4

or put (x+iy) in place of z and solve it u wil get the answers.

 

[David Hussey]

Jazakallahu khair guys! Thanks

 

[Fahm Deen]

October/November 2010/63 6(ii and iii)
Please give the solution with full explanation ASAP.
Very urgent!!

 

[istudent]

View attachment 39727

thanks man

 

[istudent]

t

View attachment 39729 this is a better diagram:

thanks man

 

[SitiPutri]

October/November 2010/63 6(ii and iii)
Please give the solution with full explanation ASAP.
Very urgent!!

Not really neat, though

 

[Snowysangel]

If you have cos^2, sin^2...you can't integrate them directly..so at first you have to conver them to integrate

Can such a question come in As?

 

[sumeru]

Can such a question come in As?

No, don't worry.....you'll have to study them in A2 ...

 

[asd]

Oct Nov 2007, Q7, part (ii) Why are we supposed to use the radian mode instead of degree mode?
http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w07_qp_3.pdf

 

[daredevil]

thankkss alot! and can u also do part ii ??

 

[daredevil]

Oct Nov 2007, Q7, part (ii) Why are we supposed to use the radian mode instead of degree mode?
http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w07_qp_3.pdf

yaar i asked a friend and she said that she doesnt know the logic of this but apparently all differential questions are solved in radians.

did u know that?? A star syed1995 ??

 

[Thought blocker]

Where is genius ?

 

[asd]

thankkss alot! and can u also do part ii ??

http://www.netcomuk.co.uk/~jenolive/vect18e.html
Here's a detailed method and I'm getting sqrt[5] using this. I did method 2.

 

[asd]

But for the same question daredevil asked, why doesn't my method work?
Here's the method sumeru:

Since they ask for the shortest distance from the point p to the line that lies ON the plane, so we can use the normal vector of the plane as the directional vector for the line equation PX, where X is a point on the plane where a line from P and the line (given in the question) on the plane intersect.
So my line equation for PX becomes: <0,2,4> +b<2,-2,3>
Now, if I put into the plane, 2x-2y+3z=1 this point, <2t, 2-2t, 4+3t> to find the value of b, and then by substituting this value into the line equation of PX, am I finding the the position vector for X where the line from P intersect the line in the equation on the plane?
Why is thisi method wrong?