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Mathematics: Post your doubts here!

daredevil

daredevil

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Faithix MFSH said:
Can someone please explain the solution to the second part of this question with detailed steps.
Would be greatly helpful if you manage to explain your steps..

Info about the paper source is in the uploaded screenshot.


Would be highly appreciated.
Click to expand...

i hope u get wat's writtenn here :p

i assumed the normal vector of the 2nd plane to be (a, b, c)
as we know that the plane is perpendicular to the other lane then their normal vectors will also b perpendicular.
according to cross product n1.n2 = 0 which gives us
a + 2b + 3c = 0

the line and the plane are parellel which means the normal vector of the plane is perpendicular to the direction vector of the line
so m.n2 = 0 gives us:
a - 2b + c = 0


i used substitution method here .. u can use elimination method too ... and solve the equations simultaneously
(4b, b, -2b) is the normal vector which when simplified gives
(4, 1, -2b)

then multiply the normal vector with the position vector of the point on the plane to get 'd'
:)
 

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minie23

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Two forces P and Q, each of magnitude 100N are inclined to each other at an angle of 60, and act on an object. Find the magnitude of the resultant P and Q.

URGENT HELP PLEASE ! :(
 
asd

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Rate of flow of the liquid into the tank: 80
Rate of flow of the liquid out of the tank: kV
Rate of change of liquid in the tank= 80-kV
dV/dt= 80 -kV

dV/(80-kV) = dt
= ∫ dV/(80-kV) = ∫ dt
= -1/k ln(80-kV) = t
= ln(80-kV) = -kt
= 80-kV= e^(-kt) + c (N.B: c = o)
= -kV= -80+ e^(-kt)
= V= (1/k)[80 - e^(-kt)]
And c is going to be zero because when t=0, there is no liquid in the tank.
M Haseeb Javed said:
View attachment 39877

Kindly solve this thanks!
Click to expand...
 
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daredevil

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upload_2014-4-22_22-1-30.png

i solved this question with the lammy's rule but i'm getting 14.75 N and 24.5N
the ms says 20N and 13N ....
HOW?!?
 
daredevil

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minie23 said:
Two forces P and Q, each of magnitude 100N are inclined to each other at an angle of 60, and act on an object. Find the magnitude of the resultant P and Q.

URGENT HELP PLEASE ! :(
Click to expand...
upload_2014-4-22_22-10-18.png

see how you hav to think on this?? i have used the head to tail rule.
after this.... use the cosine rule

c^2 = 100^2 + 100^2 -2(100)(100)Cos(130)
...
c = 181.26 N , 30` anticlockwise with the horizontal.


I hope my answer is ryt :') :p
 
asd

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I'm so happy I already gave mechanics exam last year. Stats FTW. it's so easy. :')
 
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