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Mathematics: Post your doubts here!

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d/dx(2x−11−x)

=(1−x)⋅d/dx(2x−1)−d/dx(1−x)⋅(2x−1)(1−x)2

=2⋅(1−x)−−1⋅(2x−1)(1−x)2

=2x+2⋅(1−x)−1(1−x)2

simplify:

=2x−1(1−x)2+21−x :) Is this the answer ?

You mis-interpreted the equation. The originalequation was Y = (2x-1) divided by (1-x)
 
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ummm ahem ahem... asd show off AHEM!! xD

agreed A star? :p

serioussllyyyy stats STATTSS is easy??!! :eek:
wooww....!!
LOOL. PLEEASSEE DUDE. I swear I think its easy! :p
I find mechanics harder seriously.
haha xD well then try going for commerce those with a commerce back ground or those who would generally do well in commerce do well in S1 :p and if you found S1 easy you shold have taken S1 S2 the difference is really nothing except 2 questions and increased difficulty
 
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i hope u get wat's writtenn here :p

i assumed the normal vector of the 2nd plane to be (a, b, c)
as we know that the plane is perpendicular to the other lane then their normal vectors will also b perpendicular.
according to cross product n1.n2 = 0 which gives us
a + 2b + 3c = 0

the line and the plane are parellel which means the normal vector of the plane is perpendicular to the direction vector of the line
so m.n2 = 0 gives us:
a - 2b + c = 0


i used substitution method here .. u can use elimination method too ... and solve the equations simultaneously
(4b, b, -2b) is the normal vector which when simplified gives
(4, 1, -2b)

then multiply the normal vector with the position vector of the point on the plane to get 'd'
:)


It sounds very simple that I see it explained now.
Thanks alot!
 
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