Mathematics: Post your doubts here!

[Thought blocker]

i solve the whole question and umbody else posts it lol

You think I'll do the same, then no need. I'll get it solved by others. Indeed.
Suchal Riaz
ZaqZainab
sitooon
midha.ch
Adeena Shamshir

 

[Thought blocker]

2ii. There are two possible ways to get x^2. One when the first term of the first bracket multiplies with the a term of the power x^2 from the second bracket and another when the second term of the first bracket multiplies with a term of the power x^0 of the second bracket.
Hence, (1) (60x^2) + (x^2) (6C3*(2x)^3 *(-1/2)^3)
= 60 x^2 - 20 x^2 = 40 x^2

Was it that easy ? Ty

 

[Rutzaba]

You think I'll do the same, then no need. I'll get it solved by others. Indeed.
Suchal Riaz
ZaqZainab
sitooon
midha.ch
Adeena Shamshir

the last question answer you posted... its all done on my register lol

 

[Thought blocker]

the last question answer you posted... its all done on my register lol

Kindly upload it :/

 

[Wolfgangs]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w11_qp_12.pdf

Q9, i - How to find D? The ms mentions something like vector move? How to solve such questions

 

[Rutzaba]

Kindly upload it :/

u already did lol dubara kiu karun

 

[Jelleh Belleh]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s13_qp_12.pdf
Question 2ii) , 4i),iii) , 5i), 6i), 7, 8i,ii) Please.
Some questions I am just stuck on formula like :¬
in question 4 i) dont we use : theta = cos inverse a^2 + b^2 - c^2 / 2(ab) ?
question 5i) how we got R.H.S as 10 ?
question 7) I got (3,9) what next ?

Q4:
i) First find angle COD (or BOA, both are equal):
tan@ = 10/5
@= 1.107 rad
multiply @ by 2 = 2.214 rad (this is angle COD + angle BOA)
angle BOA + angle BOC + angle COD = pi
=> pi - 2.214 = 0.9273 rad

iii) Use the formula A = (1/2)(r)^2 (@) - (1/2) (r)^2 sin

Hope everything makes sense.

 

[Rutzaba]

Dy/dx= -0.6xy

X=5e^-3t

T=0 y=70

Put y into the eq of dy/dt
- Is a minus ok?
Dy/dx= -0.6y(5e^-3t)
Dy/dt=-3ye^-3t
Putting the ts on one side aND the y on other
Dy(1/y)= dt -3e^-3t
Integrate both sides to remove the d
Lny= (-3e^-3t)/-3
ny=e^-3t +c
Wen t=0 y=70
Ln70= 1+c
C=ln70-1
Putting it bak into eq
Lny=e^-3t +ln 70 -1
Lny-ln70=e^-3t -1
By log property
Ln(y/70)= (e^-3t ) -1
y/70= e^((e^-3t)-1)
y=70 e^((e^-3t)-1)

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_33.pdf

 

[Thought blocker]

u already did lol dubara kiu karun

np

 

[Jelleh Belleh]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s13_qp_12.pdf
Question 2ii) , 4i),iii) , 5i), 6i), 7, 8i,ii) Please.
Some questions I am just stuck on formula like :¬
in question 4 i) dont we use : theta = cos inverse a^2 + b^2 - c^2 / 2(ab) ?
question 5i) how we got R.H.S as 10 ?
question 7) I got (3,9) what next ?

Q5:
i) a^2 + b^2
= (sin@ - 3cos@)^2 + (3sin@ + cos@)^2
after squaring you end up with
10sin^2@ + 10cos^2@

We know that:
sin^2@ + cos^2@ = 1
=> 10sin^2@ + 10cos^2@ = 10

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_12.pdf

Q9, i - How to find D? The ms mentions something like vector move? How to solve such questions

I prefer this way :¬
(x1,y1+x2,y2)/2 = (5,2)
(3,6 + x2,y2) = 2(5,2)
x2 = 10-3 = 7
y2 = 4-6= -2
D is (7,-2)

If someone have better way do tell us, but believe me, this method neva goes wrong

ZaqZainab
Rutzaba
Suchal Riaz

 

[Wolfgangs]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w13_qp_12.pdf

Okay, how to solve question 6(i). BTW, this sample is quite complicated

 

[Talha Khatri]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w13_qp_12.pdf

Okay, how to solve question 6(i). BTW, this sample is quite complicated

Here:

 

[Haya Ahmed]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w11_qp_13.pdf

Q9 (iii) part why is it (-5/2) <(or equal to) x < (or equal to) 0 ?

why it is not (-5/2) <(or equal to) x < (or equal to) (5/2)

Please someone explain .. Thanks

 

[Hadi Murtaza]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_13.pdf

Q9 (iii) part why is it (-5/2) <(or equal to) x < (or equal to) 0 ?

why it is not (-5/2) <(or equal to) x < (or equal to) (5/2)

Please someone explain .. Thanks

because da domain of f(x) is ≤ 0

 

[Haya Ahmed]

because da range of f(x) is ≤ 0

I still didn't get it can you explain more further please

 

[Hadi Murtaza]

I still didn't get it can you explain more further please

for f(x) , x has 2 b less than or equal to 0 , n for g(x) , x has to be less than or equal to 3, so da only inequality satisfying both conditions is dat gf(x) ≤ 0

 

[Thought blocker]

because da range of f(x) is ≤ 0

Domain or Range ? :/

 

[Thought blocker]

for f(x) , x has 2 b less than 0 , n for g(x) , x has to be less than 3, so da only inequality satisfying both conditions is dat gf(x) ≤ 0

So it is domain, not range. :/

 

[Haya Ahmed]

Ohh my god ! .. I'm confused more now !

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w11_qp_13.pdf
Q9 (iii) part why is it (-5/2) <(or equal to) x < (or equal to) 0 ?

why it is not (-5/2) <(or equal to) x < (or equal to) (5/2)


Hadi Murtaza why are we talking about domain of f(x) and g(x) while we are dealing with gf(x) equation ? isn't it something else ? please explain what is related between all the 3 functions in the domain

Thought blocker If you can explain It will be helpful you know ..