Mathematics: Post your doubts here!

[Dudu]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w13_qp_13.pdf

Q 8 . iii)

Thanks if anyone could help me.

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_1.pdf

Question 10) i ii iii, with some brief explanations. i'd like to see part i on paper if you guys can , thanks.


http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_11.pdf

Question 1) Explain, I read the answers but i don't get why

2x^2− 12x + 13 We have to do complete square method.

10i)

so, 2(x^2 -6x) +13

2(x-3)^2+13

2(x^2-6x+9) +13

2x^2-12x+18 (to remove 18 subtract it from 18 and add 13)

2(x-3)^2 -5 hence, a = 2 b = -3 and c = -5


10ii)

graph has line of symmetry on x = 3 so you'll think that A should be 3, but see 2 is out the bracket so multiply it with 3 you get A as 6


10iii)

from eqn 2(x-3)^2 - 5 put x values as zero and 6, you get range is -5 to 13


1)

 

[Dudu]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_1.pdf
Question 10) i ii iii, with some brief explanations. i'd like to see part i on paper if you guys can , thanks.

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_11.pdf
Question 1) Explain, I read the answers but i don't get why

The search button is your friend Use it!

https://www.xtremepapers.com/commun...st-your-doubts-here.9599/page-560#post-748129

EDIT: Well, nvm now ^^

 

[CЯeScɘnt]

The search button is your friend Use it!

https://www.xtremepapers.com/commun...st-your-doubts-here.9599/page-560#post-748129

EDIT: Well, nvm now ^^

its for u too

 

[Thought blocker]

The search button is your friend Use it!

https://www.xtremepapers.com/commun...st-your-doubts-here.9599/page-560#post-748129

EDIT: Well, nvm now ^^

its for u too

What is this

 

[Dudu]

its for u too

I tried lol. Couldnt find my question. :/

 

[Thought blocker]

I tried lol. Couldnt find my question. :/

what is this all ? Explain it to me please. :/

 

[Browny]

Browny kitkat <3 :P
0<1/3 tan*x>1

we want x to be subject

Multiplying by 3



0<tan*x>3

Taking under root

0< tanx>under root 3

Now tan inverse,tan inverse 0=0 and tan inverse under root 3= pi by 3
0<x>pi by 3

why is it greater than 0 rather than<-1?

 

[Faaiz Haque]

2x^2− 12x + 13 We have to do complete square method.

10i)

so, 2(x^2 -6x) +13

2(x-3)^2+13

2(x^2-6x+9) +13

2x^2-12x+18 (to remove 18 subtract it from 18 and add 13)

2(x-3)^2 -5 hence, a = 2 b = -3 and c = -5


10ii)

graph has line of symmetry on x = 3 so you'll think that A should be 3, but see 2 is out the bracket so multiply it with 3 you get A as 6


10iii)

from eqn 2(x-3)^2 - 5 put x values as zero and 6, you get range is -5 to 13


1)

Thanks but i still don't get the completing square question, any possible way you can break it down further?

Like I thought we had to take the coefficient of X, divide it by 2 and square it then add it to both sides..? but i dont understand what you did

 

[CЯeScɘnt]

why is it greater than 0 rather than<-1?

because x is greater than 0

 

[ZaqZainab]

Haya Ahmed
and i hope you know after that you use the mid point formula

 

[Ameena Eesa]

sweetheart its A level mathematics forum

ohhh okayyyy...... stilllllll, now that i have posted it can you'll help........

 

[Thought blocker]

Thanks but i still don't get the completing square question, any possible way you can break it down further?

Like I thought we had to take the coefficient of X, divide it by 2 and square it then add it to both sides..? but i dont understand what you did

Its damn easy Learn it from this site http://examsolutions.net/maths-revi...adratics/completing-the-square/tutorial-1.php

 

[CЯeScɘnt]

ohhh okayyyy...... stilllllll, now that i have posted it can you'll help........

just post them in olevel forum,somebady will surely answer it,actually i dont remember exactly all of them!

 

[Ameena Eesa]

just post them in olevel forum,somebady will surely answer it,actually i dont remember exactly all of them!

ok, ryt. but its so hectic to post stuff here............. thanks anyway

 

[Namehere]

I´ve got a question and would appreciate some help.

For Q9(i), if you are trying to find the normal to the plane using vector product, why if you do AC x AB or CA x BA you get a wrong answer, but if you use any other two vectors, you get the correct normal to the plane? The only difference for the normal to the plane I get using AC x AB or CA x BA is a minus sign for the k coordinate, instead of a positive one.

I would also like if someone could clarify me how to use vector product correctly, ie. what requisites should the vectors you are going to use for vector product have?

Thank you in advance.

Please... help me with these two questions. (Summer 2007, Paper 3)

https://www.xtremepapers.com/community/threads/mathematics-post-your-doubts-here.9599/page-603

 

[Exo_luhan]

My doubt is why for finding distance (area under graph) in p4 we take negative velocity and if they ask total distance we dnt take negative velocity?

 

[Faaiz Haque]

Question 5 whole question
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s10_qp_11.pdf

Full working please

 

[CЯeScɘnt]

My doubt is why for finding distance (area under graph) in p4 we take negative velocity and if they ask total distance we dnt take negative velocity?

negative velocity is when the particle is returning to its start point.

 

[ZaqZainab]

negative velocity is when the particle is returning to its start point.

so much like as physics