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Mathematics: Post your doubts here!

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look we will put the value of v which is 30 and t which is 10 in the equation so we will get the constant
a=-0.4t
v=-0.2t^2 +k
30=-0.2(10)^2 +K
30=-20+K
k=50
thanks a lot
one more question
http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w08_qp_4.pdf
http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w08_ms_4.pdf
question # 7ii
here in this question why aren't they taking t=0.5 and v=5 to fing k? what's the difference between these two situations?
o_O
 
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Messages
1,394
Reaction score
1,377
Points
173
thanks a lot
one more question
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w08_qp_4.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w08_ms_4.pdf
question # 7ii
here in this question why aren't they taking t=0.5 and v=5 to fing k? what's the difference between these two situations?
o_O
okay wat are u considering k??

and if u are talking about using the equations of motion to solve this then it is not valid here bcz the acceleration is not constant. we can only use the equations of motion if the aceleration is constant.
 
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