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there are only three people active on this thread and all are doing M1 paper 4. discuss.who's done with mechanics? want to discuss paper 4
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there are only three people active on this thread and all are doing M1 paper 4. discuss.who's done with mechanics? want to discuss paper 4
thanks a lotlook we will put the value of v which is 30 and t which is 10 in the equation so we will get the constant
a=-0.4t
v=-0.2t^2 +k
30=-0.2(10)^2 +K
30=-20+K
k=50
just give me a while and i'll try solving it...thanks a lot
one more question
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w08_qp_4.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w08_ms_4.pdf
question # 7ii
here in this question why aren't they taking t=0.5 and v=5 to fing k? what's the difference between these two situations?
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okay wat are u considering k??thanks a lot
one more question
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w08_qp_4.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w08_ms_4.pdf
question # 7ii
here in this question why aren't they taking t=0.5 and v=5 to fing k? what's the difference between these two situations?
![]()
Can you help me pleaseWho's done mechanics paper 4? want to discuss some problems.
Where were u stuck in this question ?
Where were u stuck in this question ?
First part ho gya ?2nd part
First part ho gya ?
Wo teko 2x + F = 55 wali eqn me , "+" 2X kaisey aya ?haan
When X = 10 ; Input it in 9X - F = 55 ; F = 35
Now F = myu R
Hence, 35 = myu (110cos30)
myu = 0.367![]()
Wo teko 2x + F = 55 wali eqn me , "+" 2X kaisey aya ?
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