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use your part i answerAny one plz help me with this question,it's urgent
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s13_qp_33.pdf
Q4 part II.
Thank u
1/(2cos(x-1/6pie))6^2
square it u should get
1/4cos^2(x-1/6pie)
take 1/4 outside, u can now write1/cos^2(x-1/6pie) as sec^2(x-1/6pie)
integrating is tan(x-1/6pie)
substitute boundary values and get the answer