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Mathematics: Post your doubts here!

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♣♠ Magnanimous ♣♠ Resonance did a good job. With help of Dharmendra sir notes I am able to solve hardest questions of A2 level. We were wrong possibly. He taught us A2 syllabus. :LOL: But now its useful. I solved this when I started my AS. :LOL:
Resonance is helping me in Biology a lot :) :)
CBSE biology syllabus is ALMOST TOTALLY different than As and A level but I am able to do it :D
 
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Can someone help me with this question?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_12.pdf
Q11 (V)
The function g : x → 4 − 3 sin x is defined for the domain 1/2π ≤ x ≤ A.

(iv) State the largest value of A for which g has an inverse.
(v) For this value of A, find the value of g−1.

Thanks! :LOL:
I am getting till Sin−1 (1/3) but not that 2.8 Why? o_O
RoOkaYya G and Rutzaba help.
ZaqZainab its P1 help. :LOL:
 
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I am getting till Sin−1 (1/3) but not that 2.8 Why? o_O
RoOkaYya G and Rutzaba help.
ZaqZainab its P1 help. :LOL:
iv)
value of A is the nxt value of turning point i.e 3pi/2
this is coz it is a 1-1 function (g has an inverse) so line y=k cuts the graph at one place only :) n this happens at max n min point only

v)
4-3sinx=3
-3sinx=-1
3sinx=1
sinx=1/3

key angle = sin inverse (1/3) =0.340

x = pi - 0.340 = 2.80 u do this coz limit is b/w 0.5 pi to 1.5 pi hence its found in 2nd quadrant
 
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iv)
value of A is the nxt value of turning point i.e 3pi/2
this is coz it is a 1-1 function (g has an inverse) so line y=k cuts the graph at one place only :) n this happens at max n min point only

v)
4-3sinx=3
-3sinx=-1
3sinx=1
sinx=1/3

key angle = sin inverse (1/3) =0.340

x = pi - 0.340 = 2.80 u do this coz limit is b/w 0.5 pi to 1.5 pi hence its found in 2nd quadrant
Thanks. :)
 
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