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Mathematics: Post your doubts here!

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i)
equate both equations (solve simultaneously)

2x^5 + 3x^3 = 2x
2x^5 + 3x^3 - 2x =0

x ( 2x^4 + 3x^3 - 2 ) = 0

x=0 and ( 2x^4 + 3x^3 - 2 ) = 0

( 2x^4 + 3x^3 - 2 ) = 0 [HENCE SHOWN]

ii)
let x^2 = y
2y^2 + 3y -2 = 0

solver for y
y= x^2
replace for the values u got as y
solve for x

:)
the last part where like y values are 0.5 and -2 so is that final ans or like what shld we do next
 
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phew!! thanks alot that was some gr8 help..
just concerning the angle, why tan theta and why is the direction as u have stated?
sorry for the trouble//
its always been tan theta :p ask ppl who discovered it xD
sorry :p
its a standard formula. its always tan theta :)

coz the resultant must be on opposite direction of other forces to maintain equilibrium n all.
directions is taken from i position always. like we do for bearing while taking position from north.
got it?
 
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