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Mathematics: Post your doubts here!

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bludlynsolja
use formula R^2= X^2 + Y^2

where X = horizontal components
Y= vertical component

solve for R
R= magnitude of of resultant force

for angle :

use formula tan theta= Y/X

theta= tan (inverse) Y/X

the direction will be anticlockwise from x plane (i direction of i,j,k position)
 
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i)
equate both equations (solve simultaneously)

2x^5 + 3x^3 = 2x
2x^5 + 3x^3 - 2x =0

x ( 2x^4 + 3x^3 - 2 ) = 0

x=0 and ( 2x^4 + 3x^3 - 2 ) = 0

( 2x^4 + 3x^3 - 2 ) = 0 [HENCE SHOWN]

ii)
let x^2 = y
2y^2 + 3y -2 = 0

solver for y
y= x^2
replace for the values u got as y
solve for x

:)
 
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i)
equate both equations (solve simultaneously)

2x^5 + 3x^3 = 2x
2x^5 + 3x^3 - 2x =0

x ( 2x^4 + 3x^3 - 2 ) = 0

x=0 and ( 2x^4 + 3x^3 - 2 ) = 0

( 2x^4 + 3x^3 - 2 ) = 0 [HENCE SHOWN]

ii)
let x^2 = y
2y^2 + 3y -2 = 0

solver for y
y= x^2
replace for the values u got as y
solve for x

:)
thanx u solved it on time have test tomorrow :eek::eek::eek::eek:
thanx a lot
 
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