- Messages
- 1,432
- Reaction score
- 6,887
- Points
- 523
thanksoh my!!
ohrite then...i shall ask them.
good luck with the exam!!
uve any more quest for today?
btw where r u from?
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
thanksoh my!!
ohrite then...i shall ask them.
good luck with the exam!!
hmm okhmm i see!!
orite then..
Then wait for Rookz to answer it.i dnt knw its link , its frm a bk
Record in the givens: OA=1760 m=1100 kg u=0 m/s SinѲ=opposite/hypotenuse=160/1760=1/11 K.E=1/2mv^2=1/2(1100)(v^2-0^2)=550v^2View attachment 48044
first part!!! how come potential energy is 1000x??? Thought blocker View attachment 48044
thank u loads!!Record in the givens: OA=1760 m=1100 kg u=0 m/s SinѲ=opposite/hypotenuse=160/1760=1/11 K.E=1/2mv^2=1/2(1100)(v^2-0^2)=550v^2
Gain in P.E=mgh*sinѲ=1100*10(x-0)*1/11=1000x
my pleasurethank u loads!!![]()
use Newtons second law odf motion or use the formula below if u want easier thoughhow to find value of alpha??
actually y dont we take h as 160 itself?my pleasure![]()
-__________-but no mass was provided
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now