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A student is chosen at random. The probability that the student estimates that the mass is greater than M grams is 0.3. Find the value of M.?? HELP PLZZ
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No. The distance if from the point on which the angle is created.how and why did you calculate the distance for modZ ... isn't it supposed to be from the (0,0) to the farthest point on the shaded region ?!
x>-1/3MATH HELP NEEDED...PLEASE HELP
How to solve this inequality question?
(3x+1)(x+1)>0
Truly its an easy question but i am confused that if we take (3x+1)>0 and (x+1)>0 then it shows answer wrong.... why is this so??????? please help
Which paper? Any link?A student is chosen at random. The probability that the student estimates that the mass is greater than M grams is 0.3. Find the value of M.?? HELP PLZZ
Draw a line from the centre of circle with centre i to the edge of the circle with centre 1.http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s13_ms_32.pdf Q9 (ii) how to find |Z|
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w13_ms_32.pdf Q8 (ii) how to find the least value of |z-w|
thanks in advance
Which paper? Any link?
This is not the complete question.
its not accurate answer.... its correct answer is x<-1 and x>-1/3.... i dont know how.x>-1/3
x> -1
-1<x<-1/3
Reply back please :/May june 2013 (41) question 3 b (ii)
its not accurate answer.... its correct answer is x<-1 and x>-1/3.... i dont know how.
place the values between the range given and values greater and less than the range. The answer will specify the given range i.e x<-1 and x>-1/3its not accurate answer.... its correct answer is x<-1 and x>-1/3.... i dont know how.
sorry,haven't done p4 yetA student is chosen at random. The probability that the student estimates that the mass is greater than M grams is 0.3. Find the value of M.?? HELP PLZZ
1) 2^x - 2^-x = 1 can be written as 2^x - 1/2^x = 1. And since y=2^x , the eqn can be written as y - 1/y = 1.please help me in doing this question... thanks in advance View attachment 50852
Great and Superb... Now i have understood it completely... Thank you very very much and may God bless you.1) 2^x - 2^-x = 1 can be written as 2^x - 1/2^x = 1. And since y=2^x , the eqn can be written as y - 1/y = 1.
You can hence form the quad eqn y^2 - 1 = y (by multiplying both sides by y) which then rearranges to give y^2 - y -1=0.
2) You can solve the quad eqn involving y to give y= 1.618 and y= -0.618 (use quadratic formula to solve or the cal)
Now since y=2^x ,
1.618= 2^x. ln both sides to give ln 1.618 = x ln 2
x = ln 1.618/ ln 2 = 0.694 correct to 3 s.f .
y = -0.618 cannot be used to find a solution for x as ln negative values are undefined.
Hope you understood! You're welcome.
Assalamualikum and hello everyone.
I'm stuck in this question, so can anyone solve it for me?Would be of great help. Thanx.
The parametric equations of a curve are
x=2ɵ+cosɵ y=ɵ+sinɵ
where 0≤ɵ≤2π
1. Find dy/dx in terms of Ɵ.
2. Show that, at points on the curve where the gradient is 3/4, the parameter Ɵ satisfies an equation of the form
5sin(Ɵ+P)=2 , where the value of P is to be stated.
3. Solve the equation in part 2 to find the two possible values of Ɵ.
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