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I just solved these for you, from which papers are they? So I check if my answers are correct
http://maxpapers.com/wp-content/uploads/2012/11/9709_Oct-Nov-2010-All-Mark-Schemes.pdfI just solved these for you, from which papers are they? So I check if my answers are correct
tht ws so nice of you tyHere you go
Hi,
5)
i) they want the KE gain of the whole system, we know that KE=1/2mv^2
We know block A mass= 5 kg and B= 16 kg
So KE of whole system = (1/2)5v^2 + (1/2)16v^2 = 10.5v^2 J
ii) a) we need the loss of PE of the system. We know that PE= mgh and we know they moved a distance of x
We also know that the loss of PE of the system= Loss of b - gain of A
Well, logically B lost PE it moved downwards, so PE Loss of b= mgh= 16(10)(x) J
Also, A gained PE it moved up the slope, use basic trigonometry to find the distance it moved vertically up in terms of x.
So PE gain of A= mgh= 5(10)(xsin30) J
Loss of PE of the system= 16(10)(x) - 5(10)(xsin30)= 160x - 25x= 135x J
b) here we need the work done against friction. We know that f=uR and work = FxD
given u= 1/root3
We have to resolve, take y axis perpendicular to slope. We have R acting upwards along y axis and we have the component of weight of A acting downwards along y axis. Now R= Wcos30=50cos30= 25root3.
So friction = uR= (1/root3)(25root3)= 25 N
So work done against friction = 25x J since it moved a distance of x
iii) we know that Gain in KE= Loss in PE - work done to oppose friction
So 10.5v^2= 135x - 25x
10.5v^2 = 110x
Multiply both sides by 2
21v^2= 220x
Hi what question are you talking about?can someone help me with this question
while calculating work done by driving force y dont we include (weight x distance) as workdone by frictional force
http://www.themusicofmath.com/wp-content/uploads/2012/09/Oct.-Nov.-2008-Paper-4-Mechanics-1.pdf
oh so sorry i forgot to write the question. it question no. 4Hi what question are you talking about?
Insert W (5.5 sin a/cos a) in the equation to get 5.5 sin^2a/cos aView attachment 52377
mmm cn u tll me hw did u get sin^2a in the encircled step?
can someone help me with this question
while calculating work done by driving force y dont we include (weight x distance) as workdone by frictional force
http://www.themusicofmath.com/wp-content/uploads/2012/09/Oct.-Nov.-2008-Paper-4-Mechanics-1.pdf
if ure tlking about que 4can someone help me with this question
while calculating work done by driving force y dont we include (weight x distance) as workdone by frictional force
http://www.themusicofmath.com/wp-content/uploads/2012/09/Oct.-Nov.-2008-Paper-4-Mechanics-1.pdf
OX = 4i + 4j + 10khttp://maxpapers.com/wp-content/uploads/2012/11/9709_w14_qp_12.pdf
Q7 Part a.. How to find AM ??? Please anyone explain me..
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