Mathematics: Post your doubts here!

[TheJDOG]

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Here's 6

 

[TheJDOG]

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Here's 10

 

[Ram97]

Toughest P1 paper??

 

[nehaoscar]

Why doesn't chain rule work during integration or differentiation when the bracket is to the power of 2?

 

[Ram97]

Why doesn't chain rule work during integration or differentiation when the bracket is to the power of 2?

Can u show the qs?

 

[nehaoscar]

Can u show the qs?

http://freeexampapers.com/A-Level/Maths/CIE/2011-Jun/9709_s11_qp_12.pdf
Last question

 

[DeadlYxDemon]

Toughest P1 paper??

M/J 2014 - V12

 

[nehaoscar]

http://freeexampapers.com/A-Level/Maths/CIE/2011-Jun/9709_s11_qp_12.pdf

Q6 - i
Why does
ff(x) = x show that the inverse f-1(x) is f(x) ?

 

[Ram97]

http://freeexampapers.com/A-Level/Maths/CIE/2011-Jun/9709_s11_qp_12.pdf
Last question

There is no need of chain rule here

 

[TheJDOG]

Question 7 plzzz quickly I have exam tomorrow

Here you go

 

[Ram97]

http://freeexampapers.com/A-Level/Maths/CIE/2011-Jun/9709_s11_qp_12.pdf

Q6 - i
Why does
ff(x) = x show that the inverse f-1(x) is f(x) ?

Maybe if you move the f to other side it will be f-1(x)

TheJDOG help please

 

[nehaoscar]

There is no need of chain rule here

Volume of revolution = pi x integral of y^2
y is given so you need to square the y

 

[nehaoscar]

Maybe if you move the f to other side it will be f-1(x)

TheJDOG help please

Ohh...
f(x) =x/f
therefore f-1(x) = f(x)
Ah thanks!

 

[Ram97]

Volume of revolution = pi x integral of y^2
y is given so you need to square the y

so why would u require chain rule??

 

[nehaoscar]

so why would u require chain rule??

y = 4x^0.5 - x
so y^2 = (4x^0.5 - x)^2

Integrate y^2 you would either expand out the bracket or use the chain rule

 

[Ram97]

y = 4x^0.5 - x
so y^2 = (4x^0.5 - x)^2

Integrate y^2 you would either expand out the bracket or use the chain rule

Oh! But I prefer expanding the bracket

 

[Ram97]

y = 4x^0.5 - x
so y^2 = (4x^0.5 - x)^2

Integrate y^2 you would either expand out the bracket or use the chain rule

How's prep?

 

[TheJDOG]

A car of mass 1100 kg starts from rest at O and travels along a road OAB. The section OA is straight,
of length 1760 m, and inclined to the horizontal with A at a height of 160m above the level of O. The
section AB is straight and horizontal (see diagram). While the car is moving the driving force of the
car is 1800N and the resistance to the car’s motion is 700 N. The speed of the car is v ms−1 when the
car has travelled a distance of x m from O.


(i) For the car’s motion from O to A, write down its increase in kinetic energy in terms of v and
its increase in potential energy in terms of x.

Increase in Potential Energy = 1000x . How ??

There you go bro

 

[nehaoscar]

Oh! But I prefer expanding the bracket

Yeah but then how come it doesn't work with chain rule... :/
See if you substitute x=16, the numerator becomes 0, so the whole thing just gives 0 .... thats wrong... have i integrated wrong?

 

[nehaoscar]

How's prep?

Good
Chem is what I'm worried about most!
Wbu?
BTW Good luck!