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OH MY GOD then i probably got 69/75
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h=90 m k=1/15Pi
So h=60(1-coskt)
60-60cos1/15Pit=90
-60cos1/15Pit=30
cos1/15Pit=-1/2
1/15Pit=2/3Pi or 4/3Pi
so t= 10 and t=20
they said "the time for which the passenger was at a height greater than 90" not "the time at which the height was 90"Wait what we had to find a range oh no I just got 10
I misread itthey said "the time for which the passenger was at a height greater than 90" not "the time at which the height was 90"
oh right.. what a stupid mark to lose hahaha :0Nope its not because cos =0.5 The angle equals to 60 degrees when its -0.5 you get 120 so you do the negative quadrants which are 120 degrees which is 2/3Pi and 240 degrees which is 4/3Pi
Yes.Do we integrate the equation :S should we open the brackets first?
Also someone explain Q10 part (iv) please? Same paper
http://maxpapers.com/wp-content/uploads/2012/11/9709_w08_qp_3.pdf
Very weird question :/
Sure!Plz some one help me out with topic permutations and combinations......
????Sure!
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