Mathematics: Post your doubts here!

nehaoscar

nehaoscar

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Ahmed Aqdam said:
Velocity after A is 10t - 0.15t^2 +C (Integrated acceleration)
This will be equal to 5 as at t=0 P is at A and that instant its velocity is 5ms-1.
So velocity after A is 10t - 0.5t^2 +5
Integrate this to get distance
5t^2 - 0.05t^3 + 5t
Time taken from O to A was 0.5s so after A will be 3.0s.
Put 2.5 in the equation to get 42.97 m after A.
Add 1.25 m from O to A. So total distance is 44.2 m.
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Oh ok thanks! i was taking time as 0.5s instead of 0 :S
 
Serial_Ripper

Serial_Ripper

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DaniyalK said:
Tension on both sides of the pulley is same, so the right angle can be split into 2 45 degree angles. If you resolve one of these, it's Tcos45.
Since there are 2 of these, the resultant is equal to 2Tcos45
2Tcos45 =4sqrt2
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I DON'T KNOW HOW TO THANK YOU!
 
sj0007

sj0007

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Hey I just have a doubt regarding paper 3 pure 3
When we make Argand diagrams can we make them on a graph paper during the exam?? Like how are they going to attach the graph paper to the answer booklet?
It might sound stupid but It just came in my mind :D
 
A

ayushUcchil

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sj0007 said:
Hey I just have a doubt regarding paper 3 pure 3
When we make Argand diagrams can we make them on a graph paper during the exam?? Like how are they going to attach the graph paper to the answer booklet?
It might sound stupid but It just came in my mind :D
Click to expand...
As far as I know you've got to do it on the lined paper itself. I just use my scale/ruler to make an accurate graph. It takes only 2-3 minutes. I use the scale of 0.5cm=1 unit.
 
sj0007

sj0007

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ayushUcchil said:
As far as I know you've got to do it on the lined paper itself. I just use my scale/ruler to make an accurate graph. It takes only 2-3 minutes. I use the scale of 0.5cm=1 unit.
Click to expand...
Hmm I also usually do this but the other day I saw graph paper in additional materials so was just thinking why would I need a graph paper in paper 3.
 
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