Mathematics: Post your doubts here!

[The Sarcastic Retard]

183?????

Need help on this question.


At a particular point of a curve y=5x^2 -12x +1 the equation of the normal is x +18y +c=0. Find the value of constant c.

 

[funky brat]

2nd part anyone?

 

[The Sarcastic Retard]

2nd part anyone?

Which year paper is this? Took hell of a time to think. Well here you go:
Let @ = theta.
sin@ = 1/2
@ = 30 and 150

Now smallest value of @ is 10;
sin(n10) = 1/2
n10 = 30
n = 3.

New range is 0 < @ < 1080
3@ = 30, 150, 390, 510, 750, 870.
@ = 10, 50, 130, 170, 250, 290.

Hence largest possible value of @ = 290.

 

[funky brat]

Which year paper is this? Took hell of a time to think. Well here you go:
Let @ = theta.
sin@ = 1/2
@ = 30 and 150

Now smallest value of @ is 10;
sin(n10) = 1/2
n10 = 30
n = 3.

New range is 0 < @ < 1080
3@ = 30, 150, 390, 510, 750, 870.
@ = 10, 50, 130, 170, 250, 290.

Hence largest possible value of @ = 290.

Umm I don't remember. Thank you anyway.

 

[The Sarcastic Retard]

Umm I don't remember. Thank you anyway.

I checked it. I m correct.
Welcome. ^_^

 

[The Chill Master]

 

[The Sarcastic Retard]

View attachment 54259

i)
E(x - 50) / 16 + (50) = 51.5
E(x - 50) = 24

E(x - 50)^2 / 16 - (24/16)^2 = 6.5^2
E(x - 50)^2 = 712

ii)
Ex = 824 + 72
Ex/n = 896 / 17 = 52.7 (3sf)

x = 72; x - 50 = 22; (x-50)^2 = 484
SD = sqrt((712 + (x - 50)^2 / 17) - (24 + (x - 50) / 17)^2) = 7.94

 

[The Chill Master]

i)
E(x - 50) / 16 + (50) = 51.5
E(x - 50) = 24

E(x - 50)^2 / 16 - (24/16)^2 = 6.5^2
E(x - 50)^2 = 712

ii)
Ex = 824 + 72
Ex/n = 896 / 17 = 52.7 (3sf)

x = 72; x - 50 = 22; (x-50)^2 = 484
SD = sqrt((712 + (x - 50)^2 / 17) - (24 + (x - 50) / 17)^2) = 7.94

How's x=72???

 

[The Sarcastic Retard]

How's x=72???

test marks is denoted by letter x.
So test mark of the 17th student is 72. Hence x in part (ii) is 72.

 

[The Chill Master]

test marks is denoted by letter x.
So test mark of the 17th student is 72. Hence x in part (ii) is 72.

Oh yeah Thanks a lot bro

 

[nawaz21]

I don't know how to calculate bearing... It is a bit complicated for me

 

[lemonrsiow]

Hi friends, can anyone show me how to do Question 4 of 9709_s14_qp_31?
It is about differential equations- I don't know why the answer has k in the answer instead of just +c.

Thanks! http://maxpapers.com/syllabus-materials/mathematics-9709-a-level/attachment/9709_s14_qp_31/

 

[The Godfather]

Q2
Q3
Q4
Anyone??

 

[nighthawk]

The Godfather . Can we use differentiation here? BTW, is the answer to Q2: x= 1/2 and minimun? Please respond fast so I am answering all of them. TIA

 

[The Godfather]

The Godfather . Can we use differentiation here? BTW, is the answer to Q2: x= 1/2 and minimun? Please respond fast so I am answering all of them. TIA

Here aer the answers:~

 

[The Sarcastic Retard]

Here aer the answers:~ View attachment 54718

oh my... :/
The Chill Master
shoaib672002

 

[papajohn]

I`m offering A level tuition in Karachi..

 

[The Sarcastic Retard]

I`m offering A level tuition in Karachi..

oh my... :/
The Chill Master
shoaib672002

 

[fatimarehman]

Please I need help in a log question. Log(2x+1)=log33. As I cannot write in that font so it should be like 3 is raise to a number to get 3.
2. 3^x . 10^2x=4.20^x-2.
3. Lg(x-1)=ln(e^2-1).
Please I need solutions urgently. Thanks.

 

[shinnyyy]

Maths immediate help required plzzz help me out

A Funnel Has A Circular Top Of Diameter 20cm And A Height Of 30cm. When The Depth Of Liquid In The Funnel Is 12cm, The Liquid Is Dripping From The Funnel At A Rate Of 0.2cm^3/s. At What Rate Is The Depth Of The Liquid In The Funnel Decreasing?
from- pure maths 1 by Hugh Neil and Douglas Quadling
page numbr 183, Question 9
I need help immediately n please explain step by step
thnx in advance........