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Well then, I cant even do the first part! Help?You should use the marking scheme for answers. Youshould then post what you did not understand from it then I can explain
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Well then, I cant even do the first part! Help?You should use the marking scheme for answers. Youshould then post what you did not understand from it then I can explain
Well then, I cant even do the first part! Help?
Hi...thanks I got everything right except the last part...when we solve 3@, we are supposed 6 answers but according to the marking scheme, only 3 answers are accepted. Why so? Or, is it because some of the answers are the same? Plz, can you see the question again?It's hard to copy paste pheta everytime, I'm using pheta=@ ok?
sin (2@+@)= sin2@cos@+ cos2@sin@ -------1
This you get in formula sheet.
Then what is sin2@ and cos2@?
sin 2@= 2sin@cos@
cos 2@= 1-2sin^2 @
Replace in first equation
2sin@cos@cos@ +(1-2sin^2 @)sin@
2sin@cos^2 @+(1-2sin^2 @)sin@
----------->cos^2 @= 1-sin^2 @
2sin@(1-sin^2 @)+ (1-2sin^2 @) sin@
2sin@-2sin^3 @+ sin@ -2sin^3 @
=3sin@ -4sin^3 @
Easy? It's all in the formula sheet you are given, you just have to substitute.
For part 2, Relatively easy you just replace x by what is given and simplify.
For part 3, solve sin 3@= 3/4
you get valueS of @ and replace in x= 2sin@/3^0.5
3. The random variable X is normally distributed with mean µ and variance 21.0. Given that P(X > 10.0) = 0.7389,(w06_6) find the value of µ.please help me out with this problem anyone! aren't we supposed to use (X-mean)/sd but the answer came wrong!
Eqn of Line : y = -3/4x + 12Hi...In the question below, I am supposed to use similar triangles in order to do the first part. Now thats the problem! I didnt know I have to use this concept for this question until I looked in the marking scheme. Now, suppose I dont have the marking scheme, how will I know this? Any idea?
View attachment 57165
Btw it is Nov 2013 P 12
Yeah.I have given 9709 P1 (12) for AS level last year.
I am giving A levels in 2016 summer and I am doing P3 (32) for maths
For P3 do I need to know P1 and P2 as well?
-45+29 = -163
A sample of 36 data values, x , gave Σ(x −45) = −148 and Σ(x −45)2=3089.
(i) Find the mean and standard deviation of the 36 values. [3]
(ii) One extra data value of 29 was added to the sample. Find the standard deviation of all 37 values.[4]
No need to solve (i) solve (ii) only.
this is a past paper question. please help!!!
if you find it diificult to solve just explain the procedure.
Assalamu alaikum ...
Can any one please explain me Question 10 Part (iii) of this paper ....
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s14_qp_32.pdf
Thanks in Advance
(12-3)/30 + (16-3)/30 + 3/30 = 5/6In a group of 30 teenagers, 13 of the 18 males watch "K&K" on TV and 3 of th 12 females watch "K&K".
(i) FInd the probability that a person chosen at random from the group is either female or watches "K&K" or both.
I tried:
12/30 + 16/30 - 3/12 = 0.6833 but the answer is 5/6 = 0.833
anyone?????
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