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Since you had taken add-maths in O-levels, you don't even need to study for P1. As far as stats is concerned, the books have nothing good to offer. I suggest you do not buy books for anything. Dive straight into the past papers and the internet can help you with the courseWhat are the best books for A-Level mathematics for P1, P3, M1 and S1?
Need to buy a book now, a couple of months left in exams.
Since you had taken add-maths in O-levels, you don't even need to study for P1. As far as stats is concerned, the books have nothing good to offer. I suggest you do not buy books for anything. Dive straight into the past papers and the internet can help you with the course
When are you giving your Math exam?
I'm done with P1 and S1, got M1 and P3 this M/J
yah...I've opted for S2 but I haven't started S2 yet...I'm still covering S1
You've got plenty of time.Have to give all four P1, P3, M1, S1 in May-June 2016.
P1 is super easy. P3 is lengthy but you can do it. As far as M1 is concerned, you've studied physics so it'd be easy for you and S1, you should focus on permutations and combinations and probability. Rest all is pretty much formula-based and easy
You've got plenty of time.
You'd easily get an A*
I'm using this book :
could you please post the paper link
Give me five minutes. Ill help you out
Give me five minutes. Ill help you out
Dm /dt = K(√M) cos (0.02t)
Inbox me all the questions you want done. Ill try my best to explain
Thankyou soooooooo much!!Dm /dt = K(√M) cos (0.02t)
dM / √m = kcos0.02t dt
ʃ dM / √m = ʃ kcos0.02t dt
(M ^(1/2)) / (1/2) = ksin0.02t/0.02 + c
Rearrange:
2√M =(ksin0.02t)/0.02 + C
Now we have t = 0 and M = 100 so just substitute inorder to find the constant C
Therefore,
2√100 = (ksin0.02(0))/0.02 + C
2(10) = 0 + C
C = 20
Now : substitute the value of C to find the relationship.
2√M = (ksin0.02t)/0.02 +20
**1/0.02 = 50
So, it will become: 2√M = 50ksin0.02t + 20
b) M = 196 and t = 50
Just plug in the values.
2√196 = 50ksin0.02(50) +20
14*2 = 50ksin0.02(50) + 20
28 = 50ksin0.02(50) + 20
28 – 20 = 50ksin0.02(50)
8 = 50ksin(1)
8/50 = ksin(1)
K = 0.19 Ans.
c) 2√M = 50ksin0.02t + 20
Make m the subject
You will get:
M = ((50ksin0.02t + 20)/2)^2
Plus in the values.
M =((50(0.19)sin0.02t + 20)/2)^2
Solve the square. And you will get around 27 or 28 as your answer
If you still have problem, Inbox me
I dont own a cellphone otherwise a picture wouldve cleared it out well. Sorry
No problem !!Thankyou soooooooo much!!
This is great! Your workings and steps are clear!!
Thanks a ton for your effort and time!!!
Im glad I helped! 
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