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last 2 parts of this questions please
how'd you solve the first one? 14C12/2?
AOA every one..........
can any body help me out with 9709/04/O/N/07.............???
Aoa,Question 2........>
sorry to write it.....
Aoa,Can anyone help me out with the second part of question no 2. (i.e the magnitude of the resultant force)
QP : OCT/NOV 2011 PAPER 41
MS : OCT/NOV 2011 PAPER 41
Paperhttp://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w09_qp_12.pdf
Markshcemehttp://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w09_ms_12.pdf
examiner report not loading
Q 7
It says that the final answer should be 156.25 not 156
Aren't we supposed to round off to 3 s.f?
So dude?
I haven't seen the question, but it must be asking for the exact answer. . .So dude?
Any idea?
Um...I posted the link to the paperI haven't seen the question, but it must be asking for the exact answer. . .
Alright, in these sort of cases, if you get an exact answer(usually up to 2 decimal places), mark schemes prefer to write it in its original form. You won't loose a mark for writing it up to 3 significant figures. The examiner report doesn't say anything about deducting a mark.Um...I posted the link to the paper
Do yourself a favour and look at the question
I don't think it says anything about an exact answer...
Alright, in these sort of cases, if you get an exact answer(usually up to 2 decimal places), mark schemes prefer to write it in its original form. You won't loose a mark for writing it up to 3 significant figures. The examiner report doesn't say anything about deducting a mark.
Guys its just that the examiner report does not mention incidence where candidates round correctly, only incidences where they do incorrect roundingThe e.r does nt say that marks of students who rounded off the answer were deducted. so i think they must have been credited
thnx bro...........Aoa,
Im taking upwards direction positive and downward direction negative
Distance travelled by particle A = 10 - distance travelled by particle B
u1t + 0.5 a1 (t)^2 = 10 - [u2t + 0.5 a2 (t)^2]
[ u1 = 12.5 , a1 = - g , u2 = 0 , a2 = -g ]
Substituting these values
12.5t - 0.5g (t)^2 = 10 - [ 0.5 g (t)^2]
12.5t - 0.5g (t)^2 + [ 0.5 g (t)^2] = 10
12.5t = 10
t = 10 / 12.5 = 0.8
height above O,
h = 12.5t - 0.5g (t)^2
h = 12.5(0.8) - 0.5(9.81) (0.8)^2
h = 10 - 3.14
h = 6.8 m
The underlined phrase means the weight of 94% of the letters have a standard deviation of 12g. So let's say the mean is 20g. 94% of the letters have a weight of something between 18g and 42g, i.e. 12g off from the mean value.I need help in W11,p61, Q5 . Please explain the interpretation of the sentence underlined.View attachment 7001
Also w11/p62 Q5View attachment 7002May Allah bless you all. JazakAllah
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