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Mathematics: Post your doubts here!

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At least one damaged tape means (P>=1) which is the same as (1-P (0)).
1-[ nC0*(0.2)^0*(0.8)^n ] >=0.85
1-(0.8)^n >=0.85
Therfore solve to get n>=8.5 so the smallest value will be n=9 (we need an integer value)
(P>=1) which is the same as (1-P (0)) so then why u didnt do any calculation based on this rule
 
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Hi guys!May someone please assist me in answering part i of question 9 for 9709/31/M/J/10.Explanation(s) and method would be helpful.Thanks in advance for your assistance :)
 
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math p3 year 05 may/june
my question is part ii)
should i solve by bringing cosec to right or the other way

upload_2016-4-3_20-16-40.png
 
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Thanks in advance :). Please show all the steps if u can :)
Find AB.
AB = 2rcos@
Area of sector ABC = 4@r^2cos^2@
Area of triangle BOA = r^2cos@sin@
Area of sector OBA = 1/2r^2(pi - 2@)
Aera of segment = area of sector OBA - Area of triangle BOA = r^2(1/2(pi - 2@) - cos@sin@)
Area of 2 segements = 2 *r^2(1/2(pi - 2@) - cos@sin@)
Total shaded region = Aera of sector ABC + area of 2 segments = 2r^2(pi/2 - @ - cos@sin@) + 4@r^2cos^2@
Now manipulate it to get r^2(pi - sin2@ + 4@cos^2@ - 2@)
Now we know Total area of shaded region = 1/2 * pir^2
So r^2(pi - sin2@ + 4@cos^2@ - 2@) = 1/2 * pir^2
So manipulating this will give us cos2@ = 2sin2@ - pi/4@

P.S. I am in hurry.. If u have any doubts in this ask me. Just to make sure in triangle OBA there are 2@ drawn in diagram below the third angle will be pi - 2@ so maybe if this can arise as ur doubt, this is the solution to it. (area of segment OBA))
 

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S1 Help :( 9709/61/O/N/13/Q4
2Z0sX.jpg
 
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Do you need help for all the parts or a particular one? And wow this is the first time I saw a spoiler button here! :)
Nevermind just solved an hour ago. Miscalculated IQR.

Erm how to use the info to plot this?
I know Mean is the position of the Peak. But how to determine the height of the peak? How to use the Variance here???
W13/O/N/61/Q1
upload_2016-4-4_2-54-30.png
 
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Nevermind just solved an hour ago. Miscalculated IQR.

Erm how to use the info to plot this?
I know Mean is the position of the Peak. But how to determine the height of the peak? How to use the Variance here???
W13/O/N/61/Q1
I dont know how to do this but seriously though how do you use that spoiler button? ;)
 
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(P>=1) which is the same as (1-P (0)) so then why u didnt do any calculation based on this rule
I did do the calculations.
If u see, P (0) = nC0*(0.2)^0*(0.8)^n = (0.8)^n [ PS " nC0 " is equal to 1 and " 0.2^0 " is also equal to 1 so you're just left with (0.8)^n ]
1-P (0) = 1-(0.8)^n
 
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