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Is the answer 1.74cm?Part (ii) help pleaseView attachment 59965
Part (ii) help pleaseView attachment 59965
(P>=1) which is the same as (1-P (0)) so then why u didnt do any calculation based on this ruleAt least one damaged tape means (P>=1) which is the same as (1-P (0)).
1-[ nC0*(0.2)^0*(0.8)^n ] >=0.85
1-(0.8)^n >=0.85
Therfore solve to get n>=8.5 so the smallest value will be n=9 (we need an integer value)
I just explained it yesterday check recent posts.Hi guys!May someone please assist me in answering part i of question 9 for 9709/31/M/J/10.Explanation(s) and method would be helpful.Thanks in advance for your assistance
To do this.math p3 year 05 may/june
my question is part ii)
should i solve by bringing cosec to right or the other way
View attachment 59981
Find AB.Thanks in advance . Please show all the steps if u can
Do you need help for all the parts or a particular one? And wow this is the first time I saw a spoiler button here!S1 Help 9709/61/O/N/13/Q4
Nevermind just solved an hour ago. Miscalculated IQR.Do you need help for all the parts or a particular one? And wow this is the first time I saw a spoiler button here!
I dont know how to do this but seriously though how do you use that spoiler button?Nevermind just solved an hour ago. Miscalculated IQR.
Erm how to use the info to plot this?
I know Mean is the position of the Peak. But how to determine the height of the peak? How to use the Variance here???
W13/O/N/61/Q1
I did do the calculations.(P>=1) which is the same as (1-P (0)) so then why u didnt do any calculation based on this rule
At least 2 observations means P (2) + P (3) + P (4)
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