- Messages
- 340
- Reaction score
- 339
- Points
- 73
GOt that!! just needed a li'l bit of activation energy to start the topic!There are 3 courses, and he can take one meal from each course. So just make selections:
Select 1 meal from the 3 meals in starter course: 3C1
Select 1 meak from 5 meals in main course. Also note that each meal is served with either new potatoes OR french fries. So you need to select any from these 2 as well. So the number of selections will become: 5C1 * 2C1
Finally select 1 meal from the Dessert course: 3C1
The total no. of possible selections can then be calculated by multiplying all the above possible selections, since these events are occuring in side by side: 3C1 * 5C1 * 2C1 * 3C1 = 90
(ii) Similarly in part (ii) you are to adapt a similar method. But now you're restricted to choosing from only courses at a time.
So you can select either Starter and Main couse, Starter and Dessert Or Main Course and Dessert.
The no. of possible selections will remain the same.
Starter + Main Course: 3C1 * 5C1 * 2C1
Starter + Dessert: 3C1 * 3C1
Main course + Dessert : 5C1 * 2C1 * 3C1
^ Sum them up to find the total possible selections. The answer will be the one you have mentioned that is 69.