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Mathematics: Post your doubts here!

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would you please tell me the reason for (June 2014 /9709/12 Q 4)
why is A(aobx) = 2 A (aob)
Thank you in advance (y)
 
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would you please tell me the reason for (June 2014 /9709/12 Q 4)
why is A(aobx) = 2 A (aob)
Thank you in advance (y)

Area of triangle AOB = 1/2
would you please tell me the reason for (June 2014 /9709/12 Q 4)
why is A(aobx) = 2 A (aob)
Thank you in advance (y)

In the guestion they tell us that AOB and AXB are equal so..
Area of triangle AOB = 1/2 r^2 sin(theta)
Area of segment AXB = 1/2 r^2 (theta) - 1/2 r^2 sin(theta)

Now since their areas are equal :
1/2 r^2 sin(theta) = 1/2 r^2 (theta) - 1/2 r^2 sin(theta)

which simplifies to: 2 sin(theta)
 
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would you please tell me the reason for (June 2014 /9709/12 Q 4)
why is A(aobx) = 2 A (aob)
Thank you in advance (y)
AOBX refers to the whole shape. So the area of AOBX, or A(aobx), equals the sum of A(aob), the triagle, and A(axb), the area between the chord and the arc.
Put in an equation, this means A(aobx) = A(aob) + A(axb)
Since A(aob) = A(axb),
A(aobx) = 2 A(aob)
 
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AOBX refers to the whole shape. So the area of AOBX, or A(aobx), equals the sum of A(aob), the triagle, and A(axb), the area between the chord and the arc.
Put in an equation, this means A(aobx) = A(aob) + A(axb)
Since A(aob) = A(axb),
A(aobx) = 2 A(aob)

thanks again
 
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im done with 9709 pastpaper........now from where should i practise.....need advice.....should i do ocr or anyone have something better than this
 
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Answers will be ax + by + cz = d + 70√2 and ax + by + cz = d - 70√2
The values of a, b, c and d are the same as you found in part (i).

Basically, the only change from answer to part (i) is that we add or subtract a number to d,
And this number is equal to the distance (14) times the modulus of n (|n|, which is √50).

Try to think by yourself why it can be done this way.
 
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(a) The first term of an arithmetic progression is −2222 and the common difference is 17. Find the value of the first positive term. [3]
(b) The first term of a geometric progression is ï3 and the second term is 2 cos 1, where 0 < 1 < 0. Find the set of values of 1 for which the progression is convergent.
can smebody plz help
 
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9 (a) The first term of an arithmetic progression is −2222 and the common difference is 17. Find the value of the first positive term. [3]
(b) The first term of a geometric progression is ï3 and the second term is 2 cos 1, where 0 < 1 < 0. Find the set of values of 1 for which the progression is convergent.
plz help
 
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