Mathematics: Post your doubts here!

[i_try9621]

View attachment 61764Q1

Square both sides
Last step will be 8a^2 > 4ax
Final answer is x < 2a

 

[Shuddho Ukil]

The whole process was done at constant speed of C. This means C's kinetic energy does not change at all.

Thank you

 

[krishnapatelzz]

 

[Thought blocker]

View attachment 61767

Check your whats app in few minutes. I know how to do this.

 

[Jennifer Rosale]

Can someone please solve this?
The coordinates of the midpoint of the line AB are (1, 2). The length of the line AB is 10 units. If the gradient of AB is 3/4, find the coordinates of A and B.

 

[Holmes]

Help needed in June 2014 9709/12 Q3 and Q4........
Thanks in advance

 

[Holmes]

November 2014 9709/12 Q8 help me...

 

[DragonCub]

Can someone please solve this?
The coordinates of the midpoint of the line AB are (1, 2). The length of the line AB is 10 units. If the gradient of AB is 3/4, find the coordinates of A and B.

 

[DragonCub]

Help needed in June 2014 9709/12 Q3 and Q4........
Thanks in advance

November 2014 9709/12 Q8 help me...

 

[xtrasaucy]

Guys I need help please !
can someone solve 9709/62/m/j/12 question 7
I am lost and stuck I checked the mark scheme but it didn't make sense to me
please solve and send a picture.
thanks in advance !!

 

[DragonCub]

Guys I need help please !
can someone solve 9709/62/m/j/12 question 7
I am lost and stuck I checked the mark scheme but it didn't make sense to me
please solve and send a picture.
thanks in advance !!

 

[Hamna naseer]

plzz help
0580/s10/22

 

[i_try9621]

View attachment 61803
plzz help
0580/s10/22

First one says sinx = cosx which happens when x = 45( from the graph)
In b), at about 66 degrees you see the difference b/w sinx and cosx is 0.5

 

[krishnapatelzz]

part (iii) can someone draw a graph for me...

 

[krishnapatelzz]

part (ii)

 

[student2]

Two particles P and Q are projected vertically upwards from horizontal ground at the same instant. The speeds of projection of P and Q are 12 m s−1 and 7 m s−1 respectively and the heights of P and Q above the ground, t seconds after projection, are hP m and hQ m respectively.

Each particle comes to rest on returning to the ground. (i) Find the set of values of t for which the particles are travelling in opposite directions. (ths is 0.7 < t < 1.2)

(ii) At a certain instant, P and Q are above the ground and 3hP = 8hQ . Find the velocities of P and Q at this instant.

cn sm1 pls help me with the 2nd part?

 

[i_try9621]

View attachment 61816part (iii) can someone draw a graph for me...

Can't draw it cuz I am on mobile but I can give coordinates
For the man (0,1.8) to (100,2.2) straight line
For the woman (0,0) to (100,3) gradient gradually decreasing (a curve)

 

[krishnapatelzz]

Can't draw it cuz I am on mobile but I can give coordinates
For the man (0,1.8) to (100,2.2) straight line
For the woman (0,0) to (100,3) gradient gradually decreasing (a curve)

how do we know it is a curve and that too with a decreasing gradient

 

[i_try9621]

how do we know it is a curve and that too with a decreasing gradient

Hoghest power of t here is 2 so the graph shoulf look like a parabola. In the equation it's '- t^2' so it's negative

 

[xtrasaucy]

can someone please send me a link to the MARK SCHEME of 9709/11/m/j/16