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i dont knw how to decide which sign to put wid inverse whn i get smthing lyk f-1 = +- √asd
thanks was just confused about which two vectors we were supposed to take for the cross product. Btw if i change the order for eg. (2-3+6).(1-2+2), the signs of the answer are different, i.e.(6+2-1), is this a big deal?direction vector of line L is (1 -2 +2)
unit vector of the plane P is also given (2 -3 +6)
now the cross product of these direction vector (1 -2 +2).(2 -3 +6) = (-6 -2 +1)
this wil be the direction vector of the line whose eq. is to be found out.
Now itx stated in the question that the line ahs a point A. we have already found out the position vector of that point "A"
make the q. of the line now. r = (3 +2 +1) +t(-6 -2 1) this is the eq. of the linE
p(x) has two rootsqstn 3 part 3 can Any one help me in it . as I have obtained the quadratic expression 2x^2 + x +2
now it cannot be quadraticaly expanded how 2 solve this
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w04_ms_3.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w04_qp_3.pdf
i knw hw to find an inverse but there is a negative sign for the root as well how do u choose...if the given equation is too complex then change it to simple form as in complete square form
and when ur simplified equation turns to be like f(x) = -√2x
then ur f-1 (x) will be in the following way
f-1: x ----> divide by 2 -----> square ----> multiply by positive sign
i.e. f-1(x) = (x/2)^2
just oppose the process u will get ur inverse equation
reword this exp plzif u see the completed square form of f(x) is (x-2)^2+3.
now as g(x) is x-2. h(x) will be x^2+3. becuz then we put the equation of gx in hx n then we get fx.
i didn't get ur problemi knw hw to find an inverse but there is a negative sign for the root as well how do u choose...
lets say f(x) = x^2 + 10 for x >= 0i didn't get ur problem
will u please elaborate ur problem
lets say f(x) = x^2 + 10 for x >= 0
thn f-1 = +- √(x) - 10
but this answr is wrong it can either be +√x or -√x
how to select ??
sm1 clear my doubt plz?lets say f(x) = x^2 + 10 for x >= 0
thn f-1 = +- √(x) - 10
but this answr is wrong it can either be +√x or -√x
how to select ??
could u please explain q9 of 9709 may 2009 p3.y = A (x^n), natural log each side to get
ln y = ln A + n (ln x)
The gradient is n and y-intercept is ln A.
Just draw the line of best fit to find the two values. It should not be hard.
e^x +e^2x=e^3x ( divide by e^x)
direction vector of line L is (1 -2 +2)unit vector of the plane P is also given (2 -3 +6)now the cross product of these direction vector (1 -2 +2).(2 -3 +6) = (-6 -2 +1)this wil be the direction vector of the line whose eq. is to be found out.Now itx stated in the question that the line ahs a point A. we have already found out the position vector of that point "A"make the q. of the line now. r = (3 +2 +1) +t(-6 -2 1) this is the eq. of the linE
thanks was just confused about which two vectors we were supposed to take for the cross product. Btw if i change the order for eg. (2-3+6).(1-2+2), the signs of the answer are different, i.e.(6+2-1), is this a big deal?
no it doesn't matter actually , they can't possibly expect all candidates to use the vectors in the same order. but if you don't mind would you give me the link to the question?thanks here's another one
no it doesn't matter actually , they can't possibly expect all candidates to use the vectors in the same order. but if you don't mind would you give me the link to the question?
nope the order doesn't matter, even in markschemes they allow for the difference in signs
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