Mathematics: Post your doubts here!

[destined007]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

Done with partial fraction..dont know the next part..kindly guide me as it comes in every paper..!

tell me the partial fraction.

 

[kamina1]

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4/(x-2) - 1/(x-1) - 2/(x+1)

 

[Saneeya]

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Stuck at a question need help

http://imageshack.us/photo/my-images/83 ... 44272.png/

Can anyone solve this question for me

 

[XPFMember]

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^ LOL Why post so many times ? One would have got answered as well !! :crazy:

Aoa!

Well, there's probably a problem with the site. Bcoz it has happened with me as well...we post it once..and when it's slow we click submit again, and this is what happens! Anyways, I've deleted the extra ones!

 

[destined007]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

please help me solve this problem with all working thanks
A(7,2) and c(1,4) are two vertices of the square ABCD
(A)FIND THE EQUATION OF THE DIAGONAL BD
(B)FIND THE COORDINATES OF B AND OF D

 

[destined007]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

Done with partial fraction..dont know the next part..kindly guide me as it comes in every paper..!

 

[destined007]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

Stuck at a question need help

http://imageshack.us/photo/my-images/83 ... 44272.png/

Can anyone solve this question for me

 

[TheDealer]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

Somebody please just help me with these freaky surds!! I don't understand anything at all!!! Give me a link or something! :/

 

[destined007]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

Somebody please just help me with these freaky surds!! I don't understand anything at all!!! Give me a link or something! :/

Here:
http://www.youtube.com/watch?v=CMnrZJeodGQ
http://www.youtube.com/watch?v=ifJyCfSGm1M

 

[TheDealer]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

Heyyy thanks mann! That worked for me!

 

[destined007]

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Welcome!

 

[Saneeya]

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thanks for the help

 

[destined007]

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Welcome.

 

[whimsical]

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can someone please help me to solve this???

e^x + e^2x=e^3x

 

[whimsical]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

I could not solve these question.Someone pleasee helpp

May/june 2008
question 6
question 8 i and ii
question 9 ii

http://xtremepapers.com/CIE/Internation ... 8_qp_3.pdf

 

[asexamskillme111]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

i just started studying for math as so my question might kinda be stupid lol
in may/june 2010 question 7
i understand the question and the differenciation part and everything
what i dont understand is why the equation is multiplied by 2 at the end
18(2x+3)^-2 X 2

i dont understand the x2. why do we multiply it by 2

 

[destined007]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

can someone please help me to solve this???

e^x + e^2x=e^3x

 

[destined007]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

I could not solve these question.Someone pleasee helpp

May/june 2008
question 6
question 8 i and ii
question 9 ii

http://xtremepapers.com/CIE/Internation ... 8_qp_3.pdf

Q6)


Q8)


Q9)

 

[destined007]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

i just started studying for math as so my question might kinda be stupid lol
in may/june 2010 question 7
i understand the question and the differenciation part and everything
what i dont understand is why the equation is multiplied by 2 at the end
18(2x+3)^-2 X 2

i dont understand the x2. why do we multiply it by 2

which paper? which variant? just attach the link to the paper.

 

[VelaneDeBeaute]

Re: Maths help available here!!! Stuck somewhere?? Ask here!

A question from Radians makes its way through the ^^crazy^^ ones !!

Q 14, Chapter 10, Core Maths

Two circles, each of the radius 14 cm, are drawn with their centers 20 cm apart. Find the length of their common chord. Find also the area common to the two circles.

Ans :: 19.6 cm, 10.8 cm2

I did the first part, How do we do the second ?? :Search: