Mathematics: Post your doubts here!

[Zishi]

please help http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_32.pdf
Q6(ii)...i am not able to find the 2nd angle.

The range is from zero to 90. Are you getting an angle which is greater than 360 degrees? If yes, then subtract it from 360 to get your second angle.

 

[Aahliya]

x0 is π + 2π/2 = 3/2 π

What value are u getting for x1 ?? just show me over here .. if u don't mind

 

[Aahliya]

The Xo is the initial value, very close to the answer. This can be any close value. That is why you may use either pi or 2pi to get the answer.

Umm.. ok nyz thanks for ur help

 

[smartangel]

http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s11_qp_33.pdf
Q7 last part..plz explain..

 

[Aahliya]

x0 is π + 2π/2 = 3/2 π

Just show me the first two steps in detail using the The iterative formula given below :

x(n+1)= tan^−1(x{n}) + π​

 

[GoodRobot]

What value are u getting for x1 ?? just show me over here .. if u don't mind

i lost the paper i was working on but i guess it was 5.09

 

[Aahliya]

i lost the paper i was working on but i guess it was 5.09

how ?? can u show me using the formula pls ??

 

[GoodRobot]

The range is from zero to 90. Are you getting an angle which is greater than 360 degrees? If yes, then subtract it from 360 to get your second angle.

the angle im getting is 154 even after subtracting from 360 and the required angle is 10.4 :\

 

[GoodRobot]

how ?? can u show me using the formula pls ??

iterative formula is x= tan^−1(x) + π
x0=3/2 π
x1=tan^−1(3/2 π) + π = 4.503
x2=tan^−1(4.503) + π=4.494
x3=tan^−1(4.494) + π = 4.493
x4=tan^−1(4.493) + π = 4.493
hence , x=4.493

 

[Zishi]

the angle im getting is 154 even after subtracting from 360 and the required angle is 10.4 :\

The angle in 4th quadrant is 360-50.8 degrees. Add arctan(3) to it to get 380.8 degrees, subtracting 360 from it and dividing by 2 gives 10.4 as the answer.

 

[GoodRobot]

The angle in 4th quadrant is 360-50.8 degrees. Add arctan(3) to it to get 380.8 degrees, subtracting 360 from it and dividing by 2 gives 10.4 as the answer.

thankss alott...i have been working on it since ages.so do we have to do this in every double angle question ?

 

[Zishi]

thankss alott...i have been working on it since ages.so do we have to do this in every double angle question ?

Yes. Np.

 

[Aahliya]

iterative formula is x= tan^−1(x) + π
x0=3/2π
x1=tan^−1(3/2π) + π = 4.503
x2=tan^−1(4.503) + π=4.494
x3=tan^−1(4.494) + π = 4.493
x4=tan^−1(4.493) + π = 4.493
hence , x=4.493

what value are u getting for tan^-1 (3π/2) ?? Have u taken π in radians or in degrees because if i take in radian then tan^-1(3π/2) = 78.02 and in degrees i m getting tan^-1(3π/2) =89.79

 

[Becky250892]

Can someone help me with a P3 Question. Paper 33 of S11 Question no 8. I do not get how to differentiate it?

The diagram shows the curve y = 5sin^3xc os2x for 0 ≤ x ≤ 1/2π, and its maximum point M.
(i) Find the x- coordinate of M.

(ii) Using the substitution u = cos x, find by integration the area of the shaded region bounded by the curve and the x-axis.

 

[OrlandoBloom<3]

http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_w11_qp_32.pdf Question 3 how do you get value of a ?

 

[Chooi1993]

Can anyone explain this to me ? Between I lost the question but this is my mock exam question .
They want us to find out the least arg which satisfied both.
Please !

The complex number are :
l z-(-2+0i) l = π/4
l z-(o+2i ) = 2

 

[GoodRobot]

what value are u getting for tan^-1 (3π/2) ?? Have u taken π in radians or in degrees because if i take in radian then tan^-1(3π/2) = 78.02 and in degrees i m getting tan^-1(3π/2) =89.79

its 3/2π,not 3π/2 and i think u dont have the right mode on your calculator coz u cant get 78.02 on rad mode

 

[Unicorn]

how did people find paper 42 today?

for me it was pretty hard

 

[princesskt]

how did people find paper 42 today?

for me it was pretty hard

for me tooooooooooooooooooooo

 

[Unicorn]

for me tooooooooooooooooooooo

ikr?! CIE are such trolls