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o/n 1o variant 32 q7....last part plz..
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link to question paper and mark scheme plzo/n 1o variant 32 q7....last part plz..
Ummm okaaayy.. Thanks anywaysdivide ( x^4 + 3x^3 + ax + 3 ) by( x^2 - x + 1)
before dividing it.. complete this eq. ( x^4 + 3x^3 + ax + 3 )
it wil be aftr completion as ( x^4 + 3x^3 ox^2 + ax + 3 ) we just added " 0x^2 " to to complete the sequence of power
now divide u wil get the value of a
part iii...????eq. of a line, AB r = a + λ( b-a ).... here a and b are the co-ordinates of the points. as given in question.
AB= r = (1 2 2) + λ( 2 2 -2)
part 2)
find eq. of the line OP by same method
r = O + λ( P-O )
co-ordinates of O are are (0 0 0) and of P are ( x y z )
now hoe to find points x y z ????
it is stated that the point P lies on the line AB
that means the co-ordinates could be
x= 1 + 2λ
y= 2 + 2λ these co-ordinates r driven frm da eq. of line AB so cud b any point on AB. so cnsider dem to b point P!!
z= 2 - 2 λ
now the line AB and OP are perpendicular so the angle in between them will be 90 degree
using this fact form an eq. (2 2 -2).( x y z ) = (magnitude of (2 2 -2)) .(magnitude of (xyz)).cos(90
cos90 = 0 so the R.H.s wil be zero
now solve the left hand side fr value of "λ"
u wil get the value now puit it in x y z and get the co-ordinate of point p
Can someone help me with June 2011 / P33 / q8. I do not get how to differentiate it?
The diagram shows the curve y = 5sin^3xc os2x for 0 ≤ x ≤ 1/2π, and its maximum point M.
(i) Find the x- coordinate of M.
(ii) Using the substitution u = cos x, find by integration the area of the shaded region bounded by the curve and the x-axis.
MJ10, Varient1, Q 9, part i .I'm not able to get the correct equation. Someone Please Help.
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_31.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_ms_31.pdf
Hey, i need some help in Math P3 ! Greatly appreciated if you do help
O/N/11 P32 Q4 !
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