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w to w^2 is the diameterhow did you find the radius?
Q8(i) I have done this before in this thread, searchThank you So Much!!!!!!!!!!!!!!
If possible can u help me with my May june 2008 doubts..on Argand diagrams
http://www.xtremepapers.com/CIE/International A And AS Level/9709 - Mathematics/9709_s08_qp_3.pdfPlease help me with the 8th one..part 1 and the 5th one part 2!!!!!
Please!!
Post the links!in ON11 P31, Q1, we found x using 'ln'. What i want to know is if there is a constant on one side do i take it as ln3 or lne^3, In this question they took ln3 while in other questions for eg, differential equations we take it as lne^3. Please Help.
This question, how can i solve it here means writing the powers down and all not too much symbols or space!
This question, how can i solve it here means writing the powers down and all not too much symbols or space!
Wait i'll tell you in afternoon after i solve this paper myself!is it possible for you to post the solution? or if you could tell the steps?
e^x = 1 + 6e^−x
Wait i'll tell you in afternoon after i solve this paper myself!
hey could you please help me with my doubt.I've posted it twice here but haven't gotten any reply.Since you've been helping a lot of people,I am asking you.e^x = 1 + 6e^−x
Using u = e^x
The equation becomes
u = 1 + 6/u
u^2 = u + 6
u^2 - u - 6 = 0
(u+2)(u-3) = 0
u = -2 or u = 3
e^x = -2
This cannot be solved as ln or lg of a negative number is undefined!
The only solution is
e^x = 3
x = ln3 / lne
x = ln3
x = 1.10
We take lne^x
but according to power rule, the power becomes coefficient
so lne^x = xlne
and lne = 1
so
xlne = x
See the notes i posted on logs above !
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