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Mathematics: Post your doubts here!

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ahh that's great.Could you please explain me q4 both parts of oct 2009 32.I am not sure how to calculate the acceptance region when the alternate hypothesis is not equal to(two tail test).What should we do?the ms doesn't help at all.please reply soon.
thanks
P.S if you have any sort of doubts of your own,I'll try to help you as well.
 
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ahh that's great.Could you please explain me q4 both parts of oct 2009 32.I am not sure how to calculate the acceptance region when the alternate hypothesis is not equal to(two tail test).What should we do?the ms doesn't help at all.please reply soon.
thanks
P.S if you have any sort of doubts of your own,I'll try to help you as well.

I'm sorrryy i don't do A level math :/ I'm only doing my As at the moment...I thought you meant variant 2 my bad :/ im really sorryyy
 
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Meeeeeeeeeeeeeeeee
okay let me get this cleared first.You are doing a level math s2 right?If so could you help me binomial in hypothesis.Not sure what we're supposed to do when the alternate hypothesis is not equal to some probability.A related question would be q4 of oct 2009 32.Please let me know asap.thanks
 
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any one?
The probability that an a% confidence interval includes only values that are lower than the population mean is 1/16. Find the value of a.

it's J/11 71
 
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plz help:1)The continuous random variable x has a normal distribution with mean mu and variance sigma^2.Given that p(x>21)=0.020and p(x<10)=0.015,calculate mean and sigma to 1 dp.
 
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HELP NEEDED:600 rounds are fired from a gun at a horizontal target 50m long which extends from 950m to 1000m in range from gun.The trajectories of the rounds all lie in the vertical plane through the gun and the target.It is found that 27 rounds fall short of the target and 69 rounds fall beyond it.Assuming that the range of rounds is normally distributed,find the mean and standard deviation of the range.Estimate the number of rounds falling within 5m of the centre ot the target.
 
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i)at st pt,dy/dx(f"(x)=0
2x-6=0
x=3
ii)intergrate f"(x)=x^2-6x+c
when x=3,y=4
-4=(3)^2-6(3)+c
c=5
f(x)=x^2-6x+5
(N11 NO 4 P11)
 
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