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statistics Chapter 2 doubt. How to solve Q1???
the ans is 0.0592, incase someone gets plz post the workings.
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statistics Chapter 2 doubt. How to solve Q1???
That's a hard one!
Maybe it has to do with parametric equations, don't u think?
points lieing on a circle means the distance from the centre to these points will be same.
check that out prove that out.
A quick search on Google gave me this: http://www.mymathforum.com/viewtopic.php?t=23065&p=92079
If the three points lie on the circumference of a circle there distances from the centre (2,0) must be same [RADIUS ]
Find the distance b/w (7,12) and (2,0)
Find the distance b/w (-3,-12) and (2,0)
Find the distance b/w (14,-5) and (2,0)
These three distances must be same!
anyone der to solve plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzstatistics Chapter 2 doubt. How to solve Q1???
link image:-can anyone plzzz help me out with question 2 and question 3.....when i tried and did it.....my answer is nt matching with the textbook answers help
can anyone plzzz help me out with question 2 and question 3.....when i tried and did it.....my answer is nt matching with the textbook answers help
can someone show me how to work this out?
View attachment 14019
Q8) part b
Please could you sketch and explain them : 1) 4sin(3x) ,0 (<or =) x ( <or=) 360
2) 9-5cos(2x) , 0 (<or =) x ( <or=) 360
3) 3+4sin(2x) , 0 (<or =) x ( <or=) 180
4)Tan(2x) , 0 (<or =) x ( <or=) 180
Thanks alot !
AoA,"Integration A2"
So there's this question on how to integrate cos^3 x. I did it by breaking it into cos^2 x and cos x, you know, the by-parts method. But i seem to be getting the wrong answer. Could anyone do it for me, so i could compare my working ?? Thankyou!
"Integration A2"
So there's this question on how to integrate cos^3 x. I did it by breaking it into cos^2 x and cos x, you know, the by-parts method. But i seem to be getting the wrong answer. Could anyone do it for me, so i could compare my working ?? Thankyou!
same here how to solve for this!?????????????????????????????????anyone
hey bro but why did u substitute f(-1) in the remainder part it is supposed to be in the original equation thats f(x) and hey also thats what we call remainder theorem right?Let f(x) = (x^2 - 1)Q(x) + ax + b
f(x) = (x-1)(x+1)Q(x) + ax + b
we know that (x+1) is a factor,
f(-1) = 0,
b-a = 0, this is equation 1,
(x-1) gives remainder of 4,
f(1) = 4,
a+b = 4 , this is equation 2,
solve simultaneous equation 1 and 2,
then you can find a and b.
hye b
hey bro but why did u substitute f(-1) in the remainder part it is supposed to be in the original equation thats f(x) and hey also thats what we call remainder theorem right?
Let f(x) = (x^2 - 1)Q(x) + ax + b
f(x) = (x-1)(x+1)Q(x) + ax + b
we know that (x+1) is a factor,
f(-1) = 0,
b-a = 0, this is equation 1,
(x-1) gives remainder of 4,
f(1) = 4,
a+b = 4 , this is equation 2,
solve simultaneous equation 1 and 2,
then you can find a and b.
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