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Mathematics: Post your doubts here!

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Assalamualaikum please help me in this question
A lift starting from rest moves downwards with constant acceleration.It covers a distance 's' in time 't',where s =1/6gt^2 .A box of mass 'm' is on the floor of the lift.Find,in terms of 'm' and 'g' , an expression for the normal contact force on the box from the lift.
 
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Assalamualaikum please help me in this question
A lift starting from rest moves downwards with constant acceleration.It covers a distance 's' in time 't',where s =1/6gt^2 .A box of mass 'm' is on the floor of the lift.Find,in terms of 'm' and 'g' , an expression for the normal contact force on the box from the lift.

the answer is it 2mg/3 ??
 
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plz help me in this question also

doubt 2.jpg

the ans for the first part is 3.5
and for the second part is 0.25(5+e^-6)
 
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Assalamualaikum please help me in this question
A lift starting from rest moves downwards with constant acceleration.It covers a distance 's' in time 't',where s =1/6gt^2 .A box of mass 'm' is on the floor of the lift.Find,in terms of 'm' and 'g' , an expression for the normal contact force on the box from the lift.
If u get to know the ans post here and mention me in the comment. will be great of you. thanks
 
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Anyone in Pakistan giving maths A-level this oct/nov?? if so please let me know. thanks
 
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which componenets??? and any one from Pakistan?? and yes what are the dates??? of paper??
M giving paper 3 and paper 7(stats) and also ya the dates are
we have p3 on 30th oct and paper 7 on 7th november!!!what about u???u complted all of the as and a2 course???right??
 
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yes the answer is the same but i want to know the method

is like this:

s = (1/6)gt^2 (given from question)
s = ut+(1/2)at^2 (what we normally know)
since it start at rest, therefore u=0,

s = (1/2)at^2 , compare with the given s = (1/6)gt^2,
we will find that a = g/3

then the force acting on the box is:
mg-R=ma
R=mg-ma
R = mg - m(g/3)
R = (2mg)/3
 
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hey i hve just started as- level....can anyone pls solve question 4B miscellenous excercise from the P1 book??? asap
 
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