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Mathematics: Post your doubts here!

Tkp

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can some1 help wiht ques 9(iii)
 

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can some1 help wiht ques 9(iii)

The mid point of AC (ie M) is also equals to the mid point of BD. Since point B has been given in the question, point D can be discovered rather easily.
The length of AD = length of any side of the square ABCD.

Hope this helps. Peace.
 
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hey guys can someone please help me out with this math - A(7,2) and C (1,4) are two vertices of a square ABCD. Find the co-ordinates B and D. Thanks!
 
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hey guys can someone please help me out with this math - A(7,2) and C (1,4) are two vertices of a square ABCD. Find the co-ordinates B and D. Thanks!
X cordinates 9/2 and 7/2
taking the gradient of diagnol and as the second diagnol is normal to first so m1m2=-1
so gradient is 3 making the eq of both diagnols we get the co ordinate by X1+X3=X2+X4
 
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By the way, it would be most appreciated if you can give me your answer to 11(i) so that I can solve (ii) for you efficiently. Peace.
 
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By the way, it would be most appreciated if you can give me your answer to 11(i) so that I can solve (ii) for you efficiently. Peace.

Hey thank you sooo much !
Yeah, my ans is : 2x + 3y - 6z = 8

Btw, do you do S1 and M1 as well ?
 
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Pls guys help me, how to get c (y-intercepy}............:sneaky: thanx....!!!
ans-:lgc=-o.6
c=0.251
 
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please could some one help me with this :?

make partial fractions

2(4x^2 + 1) /(2x+1)(2x-1)

ps the degree of power of numerator= denominator
 
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please could some one help me with this :?

make partial fractions

2(4x^2 + 1) /(2x+1)(2x-1)

ps the degree of power of numerator= denominator

You will have to do long division before using partial fractions to split things up. Hope this helps. Peace.
 
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Pls guys help me, how to get c (y-intercepy}............:sneaky: thanx....!!!
ans-:lgc=-o.6
c=0.251

I am not sure what you mean by y-intercept here,
but for lgc =-0.6, assuming that you are solving for c, then c=e^-0.6 =0.549, which is definitely not 0.251.

Hope this helps. Peace.
 
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Hey thank you sooo much !
Yeah, my ans is : 2x + 3y - 6z = 8

Btw, do you do S1 and M1 as well ?

No problem. Here are the workings for 11(ii):



Hope it helps. Peace.

(I am not exactly sure what is M1 and S1, but to me its just mathematics, so I guess it shouldn't be a problem at all).
 
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