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Integrate with respect to x:
q1. (4-x) / (x-2) (x-3)
q2. 1 / (x^2 -4)
Plz reply as soon as possible.
q1. (4-x) / (x-2) (x-3)
q2. 1 / (x^2 -4)
Plz reply as soon as possible.
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does anyone have any ideas whether cie is easier than edexcel in Maths?
Integrate with respect to x:
q1. (4-x) / (x-2) (x-3)
q2. 1 / (x^2 -4)
Plz reply as soon as possible.
These had been posted on the forum before, I just had them downloaded!Need notes for P1 plz. ASAP...
guys can any one explain how to calculate the range for a function.........i stil dun knw how to calculate it...!
1) calculate the first derevative of the functionguys can any one explain how to calculate the range for a function.........i stil dun knw how to calculate it...!
they already said leave the answer in surds..so when u do the equation x= -b ±√(b^2-4ac) / 2a u will end up with x =1/4 (-20 + √40) or 1/4(-20-√40) u can simplify it..did u get it now ?So here's this question in quadratics ..
solve the quadratic equation leaving in surds form ..
i know we have to solve with the abc formula .. but this equation does not fit in .. help please :\
---> 2(x+3)^2 = 5
I have rationalized the denominator, it is although not necessary!So here's this question in quadratics ..
solve the quadratic equation leaving in surds form ..
i know we have to solve with the abc formula .. but this equation does not fit in .. help please :\
---> 2(x+3)^2 = 5
dude tht is for stationary point of a curve.... no?1) calculate the first derevative of the function
2) equate it to zero
3) find the X- value and this the the x-coordinate of the maximum or the minimum of the range
4) find the second derevative of the function and substitute the x value if needed, if its -ve, y is at max for value of x found in step 3 and if +ve value of y is at minimum.
5) substitute your x value in the original function to find Y value needed
6) if step 4 was +ve then Y grater than or equal to value found in step 5, and if step four was -ve, then Y is smaller than or equal to value of step 5.
Hope it helps.
they already said leave the answer in surds..so when u do the equation x= -b ±√(b^2-4ac) / 2a u will end up with x =1/4 (-20 + √40) or 1/4(-20-√40) u can simplify it..did u get it now ?
thanks both got the answerr..I have rationalized the denominator, it is although not necessary!
Thats right, but the stationary point in a Quadratic curve gives you either max or min point on it and this is where our range starts.dude tht is for stationary point of a curve.... no?
ooh i see.... got it...Thats right, but the stationary point in a Quadratic curve gives you either max or min point on it and this is where our range starts.
Hope I have helped you.
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