Mathematics: Post your doubts here!

[Rutzaba]

Then you must have checked the marking scheme.. i could do that too
Btw.. a tangent does not intersect the curve..

No swt hrt i did not. And sweety a tangent intersect a curve at one point

 

[Rutzaba]

Wen it intersects at one point its called a tangent.... see the definition of tangent frst.
Then we equate discriminant to 0
Wen it does not touch discriminant is less than zero
wen it touches at two points it is greater than 0

 

[salvatore]

No swt hrt i did not. And sweety a tangent intersect a curve at one point

Wen it intersects at one point its called a tangent.... see the definition of tangent frst.
Then we equate discriminant to 0
Wen it does not touch discriminant is less than zero
wen it touches at two points it is greater than 0

Hmm yeah.. that makes sense. I was wrong about the tangent thingy.. sorry!
Thanks a lot for your help..

 

[Rutzaba]

Hmm yeah.. that makes sense. I was wrong about the tangent thingy.. sorry!
Thanks a lot for your help..

you are alwayss welcome

 

[Rutzaba]

Assume 3^y to be x, and solve the third-degree equation !!

Rutzaba Gémeaux

Lol

 

[Jspake]

http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s05_qp_1.pdf
No. 5

I have found the coordinates of M and A as:
M(4, 6) & A(−8, 0)

I couldn't find the coordinates of C.. please help me solve it

 

[Rutzaba]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s05_qp_1.pdf
No. 5

I have found the coordinates of M and A as:
M(4, 6) & A(−8, 0)

I couldn't find the coordinates of C.. please help me solve it

by properties ... m is the midpoint of AC as well as BD

 

[Jspake]

by properties ... m is the midpoint of AC as well as BD

yeah.. but how do you solve for the coordinates of C?

 

[Rutzaba]

midpoint formula
(x1 +( -8))
_______ = 4
2

 

[Iridescent]

Jspake
(x1+x2)/2, (y1+y2/2 = the mid-point i.e., m
(-8+x2)/2, (0+y2)/2 =(4,6)

(-8+x2)/2 =4
-8+x2 = 8
x2 = 8+8
x2=16


(0+y2)/2 = 6
0+y2 = 12
y2=12

Therefore coordinates of C are (16,12)

 

[Rutzaba]

http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s09_qp_1.pdf
Q 10part three.
somone solve plz

 

[Minato112]

http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s09_qp_1.pdf
Q 10part three.
somone solve plz

Do f(0) and f(A), the range will be between these two.

Hope it helps.

 

[Rutzaba]

Do f(0) and f(A), the range will be between these two.

Hope it helps.

i have no idea whether it wud or not Muhammad TAimoor

 

[Jspake]

midpoint formula
(x1 +( -8))
_______ = 4
2

Jspake
(x1+x2)/2, (y1+y2/2 = the mid-point i.e., m
(-8+x2)/2, (0+y2)/2 =(4,6)

(-8+x2)/2 =4
-8+x2 = 8
x2 = 8+8
x2=16


(0+y2)/2 = 6
0+y2 = 12
y2=12

Therefore coordinates of C are (16,12)

Thanks a lot guys..

 

[salvatore]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s06_qp_1.pdf
No. 11 (i)

Here's some of my work:

k - x = 9 / (x+2)
(x+2) x (k - x) = (x+2) x 9 / (x+2)
kx - x²2 + 2k - 2x = 9
-x² + kx - 2x + 2k - 9 = 0

b²2 - 4ac > 0
(kx - 2x²) - (4 x -x² x (2k - 9) > 0
k²x² - 4kx²2 + 4x²2 - 4x²2(2k - 9) = 0
Hence, K²x² - 12kx² + 40x² = 0

Am I correct up to this point? What next?
Please help

 

[Silent Hunter]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_41.pdf

it mechanics...... Q3 ?

 

[Rutzaba]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_41.pdf

it mechanics...... Q3 ?

Havent done mechanics so sorry.

 

[Rutzaba]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s06_qp_1.pdf
No. 11 (i)

Here's some of my work:

k - x = 9 / (x+2)
(x+2) x (k - x) = (x+2) x 9 / (x+2)
kx - x²2 + 2k - 2x = 9
-x² + kx - 2x + 2k - 9 =

A= -1 b= k-2 c= 2k-9

Am I correct up to this point? What next?
Please help

 

[Alice123]

Pls help....
8 women and 5 men are standing in a line.
In how many arrangements will no two men standing next to each other?
thanks in advance

 

[Rutzaba]

Pls help....
8 women and 5 men are standing in a line.
In how many arrangements will no two men standing next to each other?
thanks in advance

is the answer 40320?